Answer:
See explanation
Explanation:
The boiling point of a substance is affected by the nature of bonding in the molecule as well as the nature of intermolecular forces between molecules of the substance.
2-methylpropane has only pure covalent and nonpolar C-C and C-H bonds. As a result of this, the molecule is nonpolar and the only intermolecular forces present are weak dispersion forces. Therefore, 2-methylpropane has a very low boiling point.
As for 2-iodo-2-methylpropane, there is a polar C-I bond. This now implies that the intermolecular forces present are both dispersion forces and dipole interaction. As a result of the presence of stronger dipole interaction between 2-iodo-2-methylpropane molecules, the compound has a higher boiling point than 2-methylpropane.
Answer:
The definition is defined throughout the clarification section beneath, and according to the particular circumstance.
Explanation:
- Although water samples were supplemented with purified water, the amount of EDTA has would be smaller.
- Since there are fewer ions throughout purified water, most of the ions are eliminated throughout distillation, less utilized EDTA.
- Complex calcium formation including EDTA will be less complex. Samples used throughout the starting include several Ca⁺², Mg²⁺ ions that have not been found in pure water, causing fewer EDTA volume to enter the final stages.
Explanation:
mass = Moles * molar mass
molar mass of BaSO4 = 112+32+64= 208
= 1.72*208 = 357.76
Answer:The correct answer option A.
Explanation:
Q= heat removed from the water
m= mass of the water = 80 grams
c = heat capacity of water= 4.18 J/g°C
Q = -10,032 joules 
-10,000 Joules
Negative sign indicates that heat was removed from the water.
Heat removed from the water of 80 gram of water is 10,032 Joules.Hence, the correct answer option A.
