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lilavasa [31]
3 years ago
8

Please answer soon!!!!!

Chemistry
1 answer:
fgiga [73]3 years ago
5 0

Answer:

7.27 grams

Explanation:

Format= starting amount (g)·(1 mol/molar mass)·(amount of wanted/amount of starting)·(molar mass of wanted/1 mol)

41.0 x \frac{1 mol}{17.031}x\frac{3 H2}{2NH3} x\frac{2.016}{1 mol} =7.27

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Students working in lab accidentally spilled 17 l of 3.0 m h2so4 solution. they find a large container of acid neutralizer that
bogdanovich [222]

Answer is: 8568.71 of baking soda.

Balanced chemical reaction: H₂SO₄ + 2NaHCO₃ → Na₂SO₄ + 2CO₂ + 2H₂O.

V(H₂SO₄) = 17 L; volume of the sulfuric acid.

c(H₂SO₄) = 3.0 M, molarity of sulfuric acid.

n(H₂SO₄) = V(H₂SO₄) · c(H₂SO₄).

n(H₂SO₄) = 17 L · 3 mol/L.

n(H₂SO₄) = 51 mol; amount of sulfuric acid.

From balanced chemical reaction: n(H₂SO₄) : n(NaHCO₃) = 1 :2.

n(NaHCO₃) = 2 · 51 mol.

n(NaHCO₃) = 102 mol, amount of baking soda.

m(NaHCO₃) = n(NaHCO₃) · M(NaHCO₃).

m(NaHCO₃) = 102 mol · 84.007 g/mol.

m(NaHCO₃) = 8568.714 g; mass of baking soda.

4 0
3 years ago
Please help to me solve these ! :)
emmainna [20.7K]
I. The solubility of NaCl at 25 degrees C would be between the solubilities at 20 and 30 degrees C. A reasonable answer would be 36 grams/100 g water
ii. From the table, it’s clear that the salts are more soluble at higher temperatures, indicating that an increase in temperature increases solubility.
iii. At 50 degrees C, a saturated ammonium chloride solution will have 50.6 grams of salt per 100 g water. At 20 degrees C, the solution can hold only 37.3 grams of salt per 100 g water. Thus, 13.3 grams of salt will precipitate per 100 grams of water.
4 0
4 years ago
Read 2 more answers
The two gases, H2 and O2, were allowed to effuse under the same conditions through a pinhole. If the rate of effusion of O2 was
TEA [102]

The rate of effusion of H₂ : 7.2 x 10⁻² m/s

<h3>Further explanation  </h3>

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

or  

\rm M_1\times r_1^2=M_2\times r_2^2

MW₁ O₂ = 32 g/mol

MW₂ H₂ = 2 g/mol

\tt \dfrac{1.8\times 10^{-2}}{r_2}=\sqrt{\dfrac{2}{32} }\\\\\dfrac{(1.8\times 10^{-2})^2}{r_2^2}=\dfrac{2}{32}\\\\r_2=0.072=7.2\times 10^{-2}~m/s

7 0
3 years ago
2) The two solid blocks represented in the diagram are made of the same material and are under the same temperature and pressure
scoundrel [369]

Answer:

54 g

Explanation:

We'll begin by calculating the density of X. This can be obtained as follow:

Mass of X = 54 g

Length (L) = 9 cm

Breadth (B) = 2 cm

Height (H) = 1 cm

Volume of X = L × B × H

Volume of X = 9 × 2 × 1

Volume of X = 18 cm³

Density of X =?

Density = mass /volume

Density of X = 54/18

Density of X = 3 g/cm³

Finally, we shall determine the mass of Y as follow:

Length (L) = 3 cm

Breadth (B) = 3 cm

Height (H) = 2 cm

Volume of Y = L × B × H

Volume of Y = 3 × 3 × 2

Volume of Y = 18 cm³

Density of Y = Density of X (since they are made of the same material)

Density of X = 3 g/cm³

Density of Y = Density of X = 3 g/cm³

Mass of Y =.?

Density = mass /volume

3 = mass of Y /18

Cross multiply

Mass of Y = 3 × 18

Mass of Y = 54 g

5 0
3 years ago
What 2 molecules make up sucrose?
Len [333]
I think it’s glucose and fructose.
6 0
3 years ago
Read 2 more answers
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