Can u try putting this in english please
Theoretical yield is the ideal number, so we'll assume it all reacted without issue.
×
×
×
=56.3gNH↓3
When we balance the given equation
SF₆(g) + SO₃(g) → SO₂F₂(g)
We will get
SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)
Solution:
Balancing the given equaation
SF₆(g) + SO₃(g) → SO₂F₂(g)
We have to balance the given number of O
SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)
We get balanced equation
SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)
The reaction quotient will be
Qc = [product] / [reactant]
Qc = [SO₂F₂(g)] / [SF₆(g) + SO₃(g)]
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Answer:
0.095M
Explanation:
HClO4 + NaOH = NaClO4 + H2O
Concentration of acid CA= 0.170M
Concentration of base CB= ???
Volume of base VB= 28.5ml
Volume of acid VA= 16.0ml
Number of moles of acid nA= 1
Number of moles of base nB= 1
From
CAVA/CBVB= nA/nB
CB= CAVAnB/VBnA
CB= 0.170×16.0×1/28.5×1
CB= 0.095M
