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Readme [11.4K]
3 years ago
14

If the pH of a solution is 4.73, what is the pOH? *

Chemistry
1 answer:
Marizza181 [45]3 years ago
3 0
POH + pH = 14
pOH + 4.73 = 14
pOH = 14 - 4.73 = 9.27
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Use electron configurations to account for the stability of the lanthanide ions Ce4⁺ and Eu2⁺.
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4 0
2 years ago
In another experiment, the student titrated 50.0 mL of 0.100 M HC,H,O, with
____ [38]

Answer:

Eqv Pt pH = 8.73

Explanation:

    HOAc                   +            NaOH            =>            NaOAc              + H₂O

50ml(0.10M HOAc)  +  50ml(0.10M NaOH) => 100ml(0.05M NaOAc) + H₂O

For neutralized system, 100ml of 0.05M NaOAc remains

NaOAc => Na⁺ + OAc⁻

Na⁺ + H₂O => No Rxn

          OAc⁻  +  H₂O  => HOAc + OH⁻

C(i)   0.05M       -----        0M      0M

ΔC        -x           -----         +x        +x

C(f)    0.05-x      

       ≅ 0.05M    -----          x          x

Kb = Kw/Ka = [HOAc][OH⁻]/[OAc⁻] = 1 X 10⁻¹⁴/1.7 X 10⁻⁵ = (x)(x)/(0.05M)

=> x = [OH⁻] = SqrRt(0.05 x 10⁻¹⁴/1.7 x 10⁻⁵) = 5.42 x 10⁻⁶M

=> pOH = -log[OH⁻] = -log(5.42 x 10⁻⁶) = 5.27

pH + pOH = 14 => pH = 14 - pOH = 14 - 5.27 = 8.73 Eqv Pt pH

8 0
3 years ago
Thanks for the help :)
Andre45 [30]
Welcome friend '~'        happy to help
8 0
4 years ago
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