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Alenkinab [10]
4 years ago
8

Be sure to answer all parts. thallium(i) is oxidized by cerium(iv) as follows: tl+(aq) + 2ce4+(aq) → tl3+(aq) + 2ce3+(aq) the el

ementary steps, in the presence of aqueous mn(ii), are as follows: step 1: ce4+ + mn2+ → ce3+ + mn3+ step 2: ce4+ + mn3+ → ce3+ + mn4+ step 3: tl+ + mn4+ → tl3+ + mn2+ the rate law is given by the equation: rate = k[ce4+][mn2+] identify the catalyst: tl+ tl3+ ce3+ ce4+ mn2+ mn3+ mn4+ identify the intermediates: tl+ tl3+ ce3+ ce4+ mn2+ mn3+ mn4+ identify the rate-determining step
Chemistry
1 answer:
Doss [256]4 years ago
5 0
<span>Best Answer: Mn(ii) is catalyst Stetep-1 is slow step Steps-2,3 are fast steps intermediates are Mn(iii)and Mn(iv) since step -1 is slow rate depends on Ce(iv) and Mn(ii) only not on Tl(i) as it is involved in fast step-3</span>
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JulijaS [17]

Answer:

0.3936 J/gC

Explanation:

using the formula: q=mcΔt

q= 7032J

m=812g

ΔT = 22C

plug in and solve:

7032=(812)(c)(22)

c=7032/(812)(22)

c=0.39 J/gC

7 0
3 years ago
Which element have zero valency
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The answer is Helium. hope its helpful (:
4 0
3 years ago
A balloon has a pressure of 3.1 atm at a volume of 155 ml. if the temperature is held constant, what is the volume (ml) if the p
GarryVolchara [31]

Answer:

45.8 mL

Explanation:

If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.

P₁ = 3.1 atm                        P₂ = 10.5 atm

V₁ = 155 mL                       V₂ = ? mL

P₁V₁ = P₂V₂                                                 <----- Boyle's Law equation

(3.1 atm)(155 mL) = (10.5 atm)V₂                <----- Insert values

480.5 = (10.5 atm)V₂                                  <----- Multiply 3.1 and 155

45.8 = V₂                                                    <----- Divide both sides by 10.5

4 0
2 years ago
How many moles of hcl are present in 40.0 ml of a 0.035 m solution?
Elden [556K]

Answer:

0.0014 moles is present in 40cm³ of 0.035M of HCl solution

Explanation:

Molarity = 0.035M

V = 40.0mL

1mL = 1cm³

V = 40cm³

0.035 moles = 1000cm³

X moles is present in 40cm³

X = (40 * 0.035) / 1000

X = 0.0014moles

0.0014 moles is present in 40cm³ of solution

8 0
3 years ago
Please select the word from the list that best fits the definition
leonid [27]

Answer:

Systemic Circulation

Explanation:

7 0
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