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Luden [163]
3 years ago
15

Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction? A. carbon + oxyg

en + carbon dioxide B. carbon + oxygen → carbon dioxide C. carbon dioxide → carbon + oxygen D. carbon dioxide + carbon → oxygen
Chemistry
2 answers:
Naddika [18.5K]3 years ago
5 0

Carbon burns in the presence of oxygen to give carbon dioxide. The chemical equation describing this reaction is \text { carbon }+\text { oxygen } \rightarrow \text { carbon dioxide }

Answer: Option B

<u>Explanation: </u>

The chemical equations are the representation of a particular reaction.This equation used to avoid the description of the reaction and narrowing it to precise statement. It consists of two parts namely,

  • The reactants that initially present undergoes mutual reaction.
  • The products, the aftermath of the reaction.

Here Carbon and oxygen are the reactants, the arrow symbol shows the direction of the reaction and the product here is carbon dioxide.

sveticcg [70]3 years ago
3 0

Answer:

Hello my friend! The correct answer to this quastion is "B. carbon + oxygen → carbon dioxide"

Explanation:

Carbon uses oxygen and heat as fuel for the O2 chemical bond breakdown reaction, and the new reaction between carbon and formed oxygen or carbon dioxide.

C + O2 ----> CO2

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Answer:

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7 0
3 years ago
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5 0
3 years ago
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Yes it does change

Explanation:

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Water is heated to boiling and water vapor (steam) is released. Chemical change or physical change?
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68.3 grams of sodium hydroxide reacts with 78.3 grams of magnesium nitrate. ____ grams of magnesium hydroxide will form from thi
Vera_Pavlovna [14]

Answer:

30.8 grams of magnesium hydroxide will form from this reaction, and magnesium nitrate is the limiting reagent.

Explanation:

The reaction that takes place is:

  • 2NaOH + Mg(NO₃)₂ → 2NaNO₃ + Mg(OH)₂

Now we <u>convert the given masses of reactants to moles</u>, using their respective <em>molar masses</em>:

  • 68.3 g NaOH ÷ 40 g/mol = 1.71 mol NaOH
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0.528 moles of Mg(NO₃)₂ would react completely with (0.528 * 2) 1.056 moles of NaOH. There are more than enough NaOH moles, so NaOH is the reagent in excess and <em>Mg(NO₃)₂ is the limiting reagent.</em>

Now we <u>calculate how many Mg(OH)₂ are produced</u>, using the <em>moles of the limiting reagent</em>:

  • 0.528 mol Mg(NO₃)₂ * \frac{1molMg(OH)_2}{1molMg(NO_3)_2} = 0.528 mol Mg(OH)₂

Finally we convert Mg(OH)₂ moles to grams:

  • 0.528 mol Mg(OH)₂ * 58.32 g/mol = 30.8 g
7 0
3 years ago
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