PLS HELP ASAP TY. What kind of bond would many atoms of the same metal make?

what acid-base properties can determine if a household chemical is an acid, base, or neutral substance.

damaskus [11]

if it is edible you can taste it if it taste bitter its a base and if it taste sour then it is a acid if it taste like nothing like water would it would be a neutral substance.you could also order a ph tester which is just a liquid that you drop in it.

yw:)

8 0

3 years ago

The cubic centimeter, which is often abbreviated as cc or cm3, is a metric unit for

serg [7]

Answer:

Volume

Explanation:

Cubic centimeters are used to measure the space an object takes up, or its volume.

7 0

3 years ago

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HELP !!!!!! An object moving forward at 10 m/s suddenly begins moving backward at 5 m/s. What is the most accurate explanation f

Nana76 [90]

It moves backwards 5m/s slower that forward

8 0

3 years ago

What are the concentrations of A , A, B , B, and C C at equilibrium if, at the beginning of the reaction, their concentrations a

Elenna [48]

The question is incomplete, here is the complete question:

A reaction

$A+B\rightleftharpoons C$

has a standard free-energy change of -4.88 kJ/mol at 25°C

What are the concentrations of A, B, and C at equilibrium if at the beginning of the reaction their concentrations are 0.30 M, 0.40 M and 0 M respectively?

Answer: The equilibrium concentrations of A, B and C are 0.117 M, 0.217 M, 0.183 M respectively.

Explanation:

Relation between standard Gibbs free energy and equilibrium constant follows:

$\Delta G^o=-RT\ln K_c$

where,

$\Delta G^o$ = Standard Gibbs free energy = -4.88 kJ/mol = -4880 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = $8.314J/K mol$

T = temperature = $25^oC=[273+25]K=298K$

$K_c$ = equilibrium constant of the reaction

Putting values in above equation, we get:

$-4880J/mol=-(8.3145J/Kmol)\times 298K\times \ln K_c\\\\K_c=7.17$

We are given:

Initial concentration of A = 0.30 M

Initial concentration of B = 0.40 M

Initial concentration of C = 0 M

The chemical reaction follows:

$A+B\rightleftharpoons C$

Initial: 0.30 0.40 0

At eqllm: 0.30-x 0.40-x x

The expression of equilibrium constant for the above reaction follows:

$K_c=\frac{[C]}{[A][B]}$

We are given:

$K_c=7.17$

Putting values in above equation, we get:

$7.17=\frac{x}{(0.30-x)\times (0.40-x)}\\\\x=0.183,0.657$

Neglecting the value of x = 0.657, because change cannot be greater than the initial concentration

So, equilibrium concentration of A = $(0.30-x)=(0.30-0.183)=0.117M$

Equilibrium concentration of B = $(0.40-x)=(0.40-0.183)=0.217M$

Equilibrium concentration of C = $x=0.183M$

Hence, the equilibrium concentrations of A, B and C are 0.117 M, 0.217 M, 0.183 M respectively.

5 0

3 years ago

If substance A has a density of 2.3 g/mL and water has a density of 1.00 g/mL will substance A float or sink in water? Explain i

UkoKoshka [18]

Substance A will sink because it is more dense than water. An object that is more dense than water will sink and an object that is less dense than water will float.

5 0

3 years ago