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3 years ago

If 4.5 mol of C6H8O7 react, how many moles of CO2 and Na3C6H5O7 will be produced?

Chemistry

1 answer:

Salsk061 [2.6K]3 years ago

5 0

Answer:

A. 13.5 moles of CO2

B. 4.5 moles of Na3C6H5O7

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

3NaHCO3(aq) + C6H8O7(aq) → 3CO2(g) + 3H2O(s) + Na3C6H5O7(aq)

A. Determination of the number of mole CO2 produced from the reaction. This is illustrated below:

From the balanced equation above,

1 mole of C6H8O7 reacted to produce 3 moles of CO2.

Therefore, 4.5 moles of C6H8O7 will react to produce = 4.5 x 3 = 13.5 moles of CO2.

From the above calculation, 13.5 moles of CO2 is produced

B. Determination of the number of mole of Na3C6H5O7 produced by the reaction. This is illustrated below:

From the balanced equation above,

1 mole of C6H8O7 produced 1 mole of Na3C6H5O7.

Therefore, 4.5 moles of C6H8O7 will also produce 4.5 moles of Na3C6H5O7.

Therefore, 4.5 moles of Na3C6H5O7 is produced from the reaction.

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A mineral consisted of 29.4% calcium, 23.5% sulfur and 47.1% oxygen. What is the empirical formula?

inessss [21]

Step one calculate the moles of each element
that is moles= % composition/molar mass
molar mass of Ca = 40g/mol, S= 32 g/mol , O= 16 g/mol

moles of Ca = 29.4 /40g/mol=0.735 moles, S= 23.5/32 =0.734 moles, O= 47.1/16= 2.94 moles

calculate the mole ratio by dividing each mole with smallest mole that is 0.734
Ca= 0.735/0.734= 1, S= 0.734/0.734 =1, O = 2.94/ 0.734= 4
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Is CH3NH2O ionic or covalent

Ivahew [28]

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Explanation:

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kap26 [50]

Answer:

1) 950 mL

2) 625 mmHg

3) 426 mL

Explanation:

1) This is the relationship between pressure and volume. This relationship looks like this:

P1*V1 = P2*V2

This means the first pressure times the initial volume is equal to the second pressure times the second volume. We are solving for the second volume. First, convert the mmHg to atm and the mL to L.

1 L * 1 atm = 1.053 atm * X

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2) This is the same concept as the last one. :) We don't have to convert the mmHg to atm since the answer wants it in mmHg.

750 mmHg * 0.25 L = 0.3 L * X

X = 625 mmHg

3) The relationship between volume and temperature is similar to the one between pressure and temperature (like the problem in your last question). Remember to convert degrees C to Kelvin and mL to L.

V1 / T1 = V2 / T2

0.4 L / 303 K = X / 323 K

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These problems become much easier once you learn the relationships between the different variables (temp, pressure, volume, etc.) When you have a problem like this, I like to first determine what relationship I am dealing with and then write out what I have and what I am solving for. This helps with organizing the problem. Then just solve it like a normal algebra problem. Always remember to convert temp to Kelvin, mL to L, and pressure to atm (unless it wants it in a different unit, then just make sure all the units match).

Good luck with you studies! :)

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