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3 years ago

If 4.5 mol of C6H8O7 react, how many moles of CO2 and Na3C6H5O7 will be produced?

Chemistry

1 answer:

Salsk061 [2.6K]3 years ago

5 0

Answer:

A. 13.5 moles of CO2

B. 4.5 moles of Na3C6H5O7

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

3NaHCO3(aq) + C6H8O7(aq) → 3CO2(g) + 3H2O(s) + Na3C6H5O7(aq)

A. Determination of the number of mole CO2 produced from the reaction. This is illustrated below:

From the balanced equation above,

1 mole of C6H8O7 reacted to produce 3 moles of CO2.

Therefore, 4.5 moles of C6H8O7 will react to produce = 4.5 x 3 = 13.5 moles of CO2.

From the above calculation, 13.5 moles of CO2 is produced

B. Determination of the number of mole of Na3C6H5O7 produced by the reaction. This is illustrated below:

From the balanced equation above,

1 mole of C6H8O7 produced 1 mole of Na3C6H5O7.

Therefore, 4.5 moles of C6H8O7 will also produce 4.5 moles of Na3C6H5O7.

Therefore, 4.5 moles of Na3C6H5O7 is produced from the reaction.

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Two objects are brought into contact Object 1 has mass 0.76 kg, specific heat capacity 0.87) g'c and initial temperature 52.2 'C

taurus [48]

Answer:

$T_F=77.4\°C$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:

$Q_1=-Q_2$

In terms of mass, specific heat and temperature change is:

$m_1C_1(T_F-T_1)=-m_2C_2(T_F-T_2)$

Now, solve for the final temperature, as follows:

$T_F=\frac{m_1C_1T_1+m_2C_2T_2}{m_1C_1+m_2C_2}$

Then, plug in the masses, specific heat and temperatures to obtain:

$T_F=\frac{760g*0.87\frac{J}{g\°C} *52.2\°C+70.7g*3.071\frac{J}{g\°C}*154\°C}{760g*0.87\frac{J}{g\°C} +70.7g*3.071\frac{J}{g\°C}} \\\\T_F=77.4\°C$

Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.

Regards!

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3 years ago

What is the volume of a rock that has a mass of 50 grams and a density of<br> 5 g/ml?

Brut [27]

Explanation:

density = mass/ volume

so,

volume = mass/ density

volume = 50 g/ 5 g/ml³

volume = 10 ml³

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3 years ago

What equipment might you use to find the SHC of a material? Need to know the answer ASAP PLZ

algol [13]

Theses can include the power supply circuit a joule meter to measure the energy transferred which makes the calculations a lot easier.

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3 years ago

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stiks02 [169]

Magnesium oxide is an ionic compound with a very high melting point and which requires a large amount of energy for melting.

<h3>What are ionic compounds?</h3>

Ionic compounds are compounds which are formed between oppositely charged ions which are held together by electrostatic forces of attraction between the oppositely charged ions.

Ionic compounds are formed when metal atoms donate electrons to non-metals atoms to form ions.

Magnesium oxide is an ionic compound.

The nature of bonding is ionic bonding.

It has a crystalline lattice structure.

The forces of attraction is electrostatic forces of attraction.

It has a high melting point of 2,852 °C, and thus requires a large amount of energy go melting to occur.

Therefore, magnesium oxide is an ionic compound which requires a large amount of energy for melting.

Learn more about ionic compounds at: brainly.com/question/11638999

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2 years ago

What amount of sucrose (C12H22O11) should be added to 5.83 mol water to lower the vapor pressure of water at 50 °C to 72.0 torr?

Triss [41]

Answer:

The amount of sucrose that must be added is 1.66 moles

Explanation:

Colligative property of lowering vapor pressure has this formula:

Vapor pressure of pure solvent (P°) - Vapor pressure of solution = P° . Xm

We have both vapor pressure (pure solvent and solution9, so let's determine the ΔP

ΔP = 92.6 Torr - 72 Torr = 20.6 Torr

Let's add the data in the formula

20.6 Torr = 92.6 Torr . Xm

Xm = Mole fraction of solute → (mol of solute/ mol of solute + mol of solvent)

Mol of solvent = 5.83 mol (data from the problem)

Therefore Xm = 20.6 Torr / 92.6 Torr → 0.222

Let's find out the moles of solute (our unknown value)

0.22 = moles of solute / moles of solute + 5.83 moles of solvent

0.222 (moles of solute + 5.83 moles of solvent) = moles of solute

0.222 moles of solute + 1.29 moles of solvent = moles of solute

1.29 moles of solvent = moles of solute - 0.222 moles of solute

1.29 moles = 0.778 moles of solute

1.29 / 0.778 = moles of solute → 1.66 moles

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3 years ago