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enot [183]
3 years ago
15

If 4.5 mol of C6H8O7 react, how many moles of CO2 and Na3C6H5O7 will be produced?

Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
5 0

Answer:

A. 13.5 moles of CO2

B. 4.5 moles of Na3C6H5O7

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

3NaHCO3(aq) + C6H8O7(aq) → 3CO2(g) + 3H2O(s) + Na3C6H5O7(aq)

A. Determination of the number of mole CO2 produced from the reaction. This is illustrated below:

From the balanced equation above,

1 mole of C6H8O7 reacted to produce 3 moles of CO2.

Therefore, 4.5 moles of C6H8O7 will react to produce = 4.5 x 3 = 13.5 moles of CO2.

From the above calculation, 13.5 moles of CO2 is produced

B. Determination of the number of mole of Na3C6H5O7 produced by the reaction. This is illustrated below:

From the balanced equation above,

1 mole of C6H8O7 produced 1 mole of Na3C6H5O7.

Therefore, 4.5 moles of C6H8O7 will also produce 4.5 moles of Na3C6H5O7.

Therefore, 4.5 moles of Na3C6H5O7 is produced from the reaction.

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Answer:-

2328.454 grams

Explanation:-

Volume V = 18.4 litres

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Using the relation PV = nRT

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Plugging in the values

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1 mol of O2 is produced from 2 mol of KNO3.

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