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azamat
3 years ago
8

What is the maximum amount of NaCl that can dissolve in 300 g of water? (the solubility of NaCl is 36.2 g/100 g H2O at 20 ⁰C.) p

lease don't do the work.
What chemistry equation do I have to use to solve this? 
Chemistry
1 answer:
stellarik [79]3 years ago
5 0
102g is the amount that can be dissolved   
You might be interested in
HELPPP
Ksivusya [100]
3 I’m pretty sure maybe
4 0
3 years ago
Duncan takes a break from studying and goes to the gym to swim laps If swimming burns amount of time ? 85 * 10 ^ 5 cal per hour
Volgvan

When 6.85×10⁵ cal is converted to kilojoules, the result obtained is 2866.04 KJ

<h3>Data obtained from the question </h3>
  • Energy (cal) = 6.85×10⁵ cal
  • Energy (KJ) =?

<h3>Conversion scale </h3>

1 cal = 0.004184 KJ

<h3>How to convert 6.85×10⁵ cal to kilojoules</h3>

1 cal = 0.004184 KJ

Therefore,

6.85×10⁵ cal = 6.85×10⁵ × 0.004184

6.85×10⁵ cal = 2866.04 KJ

Thus, 6.85×10⁵ cal is equivalent to 2866.04 KJ

Learn more about conversion:

brainly.com/question/2139943

6 0
2 years ago
Determine the oxidation number of each element in these compounds or ions. (a) au2(seo4)3 (gold(iii) selenate) au = se = o = (b)
Stels [109]
<span>                                                    Au</span>₂(SeO₄)₃

                                         O = -2 × 4 = -8
                                             Se  =  + 6
So,
                                            (+6 - 8) = -2

Means (SeO₄) contains -2 charge, Now multiply -2 by 3
                                             
                                             -2 ₓ 3 = -6
Means,
                             Au₂ + (-6) = 0
               
                            Au₂  = +6
Or,
                            Au  =  6 / 2

                            Au  = +3
Result:
                            Au  =  +3
                            Se  =  +6
                            O   =  -2

                                                      Ni(CN)₂


Cyanide (CN⁻) contains -1 charge,
So,
                              N  =  -3
                              C  =  +2
Then,
                                         Ni + (-1)₂  =  0

                                               Ni - 2  =  0
Or,
                                                     Ni =  +2
Result:
                            N  =  -3
                            C  =  +2
                           Ni  =  +2




6 0
3 years ago
Which type of wires (copper, aluminum, or string) are ferromagnetic metals and why?
nalin [4]

Answer: Copper isn't ferromagnetic,

Aluminum isn't ferromagnetic,

String has a ferromagnetic property

Explanation: first of all it is important to understand that all materials have diamagnetic effect.

From this we can explain two distinct property which is Paramagnetism and Ferromagnetism.

1.What do we understand by a paramagnetic material?

Ans- this describes a material that doesn't retain it's magnetic property even when the magnetic field has been removed, an example is Aluminum.

2. Ferromagnetic materials describes those type of materials that even after the removal of magnetic field retains it's magnetism. A good example of this is Iron, nickel etc.

By definition ferromagnetism is a basic property ( which depends on temperature, crystal Structure, chemical composition, etc.) That gives a material that attraction to magnet's and can form permanent magnet.

So from the examples listed in the question,

1. copper doesn't follow as a ferromagnetic material because it requires so much magnetic field to operate and is so weakly magnetized.

2. We already established aluminium as a paramagnetic material because of its weak ability to retain magnetism in the absence of magnetic field.

3. String because of its component which is (iron+carbon) has the ability to form ferrous metals.

4 0
3 years ago
If acetic acid is the only acid that vinegar contains (ka=1.8×10−5), calculate the concentration of acetic acid in the vinegar.
kicyunya [14]
Ethanoic (Acetic) acid is a weak acid and do not dissociate fully. Therefore its equilibrium state has to be considered here.

CH_{3}COOH \ \textless \ ---\ \textgreater \   H^{+} + CH_{3}COO^{-}

In this case pH value of the solution is necessary to calculate the concentration but it's not given here so pH = 2.88 (looked it up)

pH = 2.88 ==> [H^{+}]  = 10^{-2.88} =  0.001 moldm^{-3}

The change in Concentration Δ [CH_{3}COOH]= 0.001 moldm^{-3}


                                  CH3COOH          H+           CH3COOH    
Initial  moldm^{-3}                      x           0                     0
                                                                                                                       
Change moldm^{-3}        -0.001            +0.001           +0.001
                                                                                                       
Equilibrium moldm^{-3}      x- 0.001      0.001             0.001
                                                                              

Since the k_{a} value is so small, the assumption 
[CH_{3}COOH]_{initial} = [CH_{3}COOH]_{equilibrium} can be made.

k_{a} = [tex]= 1.8*10^{-5}  =  \frac{[H^{+}][CH_{3}COO^{-}]}{[CH_{3}COOH]} =  \frac{0.001^{2}}{x}

Solve for x to get the required concentration.

note: 1.)Since you need the answer in 2SF don&t round up values in the middle of the calculation like I've done here.

         2.) The ICE (Initial, Change, Equilibrium) table may come in handy if you are new to problems of this kind

Hope this helps! 



8 0
3 years ago
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