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k0ka [10]
3 years ago
12

A 125kg man buy a 6kg watermelon, a 3kg cantaloupe, and 6kgs of potatoes, he walks home with his purchases in a large bag. His w

alking speed is 2.5m/s2 , what force is required for him to get home?
Physics
1 answer:
Stells [14]3 years ago
5 0

Answer:

350N

Explanation:

Given parameters:

Mass of the man = 125kg

Mass of the watermelon = 6kg

Mass of cantaloupe  = 3kg

Mass of potatoes  = 6kg

Acceleration  = 2.5m/s²  

Unknown:

Force required to get home  = ?

Solution:

To find this force we use;

    Force  = mass x acceleration

mass  = 125 + 6 + 3 + 6  = 140kg

 So;

      Net force = 140 x 2.5  = 350N

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4 years ago
Digital thermometers often make use of thermistors, a type of resistor with resistance that varies with temperature more than st
Nezavi [6.7K]

Answer:

The temperature coefficient of resistivity for a linear thermistor is 1.38\times10^{-3}^{\circ}C^{-1}

Explanation:

Given that,

Initial temperature = 0.00°C

Resistance = 75.0 Ω

Final temperature = 525°C

Resistance = 275 Ω

We need to calculate the temperature coefficient of resistivity for a linear thermistor

Using formula for a linear thermistor

R=R_{0}(1+\alpha\Delta T)

R=R_{0}+R_{0}\alpha\Delta T

\alpha=\dfrac{R-R_{0}}{R_{0}\Delta T}

Put the value into the formula

\alpha=\dfrac{275-75}{275\times(525-0)}

\alpha=1.38\times10^{-3}^{\circ}C^{-1}

Hence, The temperature coefficient of resistivity for a linear thermistor is 1.38\times10^{-3}^{\circ}C^{-1}

4 0
3 years ago
Read 2 more answers
What is the strength of electric field EpEp 0.60 mmmm from a proton? Express your answer to two significant figures and include
disa [49]

Answer:

3.99*10^-3N/C

Explanation:

Using

Ep= kq/r²

Where r = 0.6mm = 0.6*10^-3m

K= 8.9*10^9 and q= 1.6*10^-19

So = 8.9*10^9 * 1.6*10^-19/0.6*10^-3)²

= 3.99*10^-3N/C

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Element. The answer is A.
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4 years ago
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Likurg_2 [28]

Answer:

0.34 s

Explanation:

Given that,

Initial speed of a ball, u = 5.8 m/s

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The vertical component of velocity will be,

u_y=u\sin\theta\\\\=5.8\times \sin 17\\\\=1.69\ m/s

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t=\dfrac{2u_y}{g}\\\\t=\dfrac{2\times 1.69}{9.8}\\\\t=0.34\ s

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