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k0ka [10]
3 years ago
12

A 125kg man buy a 6kg watermelon, a 3kg cantaloupe, and 6kgs of potatoes, he walks home with his purchases in a large bag. His w

alking speed is 2.5m/s2 , what force is required for him to get home?
Physics
1 answer:
Stells [14]3 years ago
5 0

Answer:

350N

Explanation:

Given parameters:

Mass of the man = 125kg

Mass of the watermelon = 6kg

Mass of cantaloupe  = 3kg

Mass of potatoes  = 6kg

Acceleration  = 2.5m/s²  

Unknown:

Force required to get home  = ?

Solution:

To find this force we use;

    Force  = mass x acceleration

mass  = 125 + 6 + 3 + 6  = 140kg

 So;

      Net force = 140 x 2.5  = 350N

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3 years ago
What is the net force acting on the object above?
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8 0
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Read 2 more answers
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const2013 [10]

Answer:

Kevin wants to make the firm private

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6 0
3 years ago
Calcular el módulo del vector resultante de dos vectores fuerza de 9 [N] y 12 [N] concurrentes en un punto o, cuyas direcciones
sdas [7]

Answer:

a) 20.29N

b) 19.43N

c) 15N

Explanation:

To find the magnitude of the resultant vectors you first calculate the components of the vector for the angle in between them, next, you sum the x and y component, and finally, you calculate the magnitude.

In all these calculations you can asume that one of the vectors coincides with the x-axis.

a)

F_R=(9cos(30\°)+12)\hat{i}+(9sin(30\°))\hat{j}\\\\F_R=(19.79N)\hat{i}+(4.5N)\hat{j}\\\\|F_R|=\sqrt{(19.79N)^2+(4.5N)^2}=20.29N

b)

F_R=(9cos(45\°)+12)\hat{i}+(9sin(45\°))\hat{j}\\\\F_R=(18.36N)\hat{i}+(6.36N)\hat{j}\\\\|F_R|=\sqrt{(18.36N)^2+(6.36N)^2}=19.43N

c)

F_R=(9cos(90\°)+12)\hat{i}+(9sin(90\°))\hat{j}\\\\F_R=(12N)\hat{i}+(9N)\hat{j}\\\\|F_R|=\sqrt{(12N)^2+(9N)^2}=15N

7 0
3 years ago
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