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3 years ago

The standard unit of work in the metric system is named after the scientist _____.

Physics

2 answers:

Lena [83]3 years ago

7 0

James Prescott Joule (1818 - 1889)

Harlamova29_29 [7]3 years ago

4 0

Answer: Hello there! The standard unit of work in the metric system, the joule, is named after the James Prescott Joule (1819 -1889), where a joule is $j = \frac{kg*m}{s^{2} }$ . He was a physicist who did a lot of work with thermodynamics, for example, he worked on the Joule-Thomson effect.

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A wave pulse travels along a string at a speed of 200 cm/s. What will be the speed if:

34kurt

Answer:

a) $v_f = \sqrt{\frac{2TL}{m}} = \sqrt{2} v = \sqrt{2}2m/s =2.83 m/s$

The velocity increase by a factor of $\sqrt{2}$

b) $v_f = \sqrt{\frac{TL}{4m}} = \frac{1}{2} v = \frac{1}{2} *2m/s =1 m/s$

The velocity decrease by a factor of 2.

c) $v_f = \sqrt{\frac{4TL}{m}} = 2} v = 2 *2m/s =4m/s$

The velocity increase by a factor of 2

d) $v_f = \sqrt{\frac{4TL}{4m}} = v = 2m/s$

The velocity not changes.

Explanation:

For this case we know that the velocity is $v = 200 cm/s = 2m/s$

$v_f$ represent the final velocity after the changes specified,

Part a

The formula for the speed of a wave in a string is given by:

$v = \sqrt{\frac{T}{\rho}}$

And the linear density is defined as:

$\rho = \frac{m}{L}$

And if we replace this we got:

$v = \sqrt{\frac{TL}{m}}$

If the tension mass is doubled we have this:

$v_f = \sqrt{\frac{2TL}{m}} = \sqrt{2} v = \sqrt{2}2m/s =2.83 m/s$

The velocity increase by a factor of $\sqrt{2}$

Part b

If we mass is quadrupled we have this:

$v_f = \sqrt{\frac{TL}{4m}} = \frac{1}{2} v = \frac{1}{2} *2m/s =1 m/s$

The velocity decrease by a factor of 2.

Part c

If the length is quadrupled we have this:

$v_f = \sqrt{\frac{4TL}{m}} = 2} v = 2 *2m/s =4m/s$

The velocity increase by a factor of 2

Part d

For this case we know that the mass and the length are both quadrupled and we got:

$v_f = \sqrt{\frac{4TL}{4m}} = v = 2m/s$

The velocity not changes.

7 0

3 years ago

A truck is hauling a 300-kg log out of a ditch using a winch attached to the back of the truck. Knowing the winch applies a cons

Pie

Answer:

0.128 s

Explanation:

We have to start by calculating the net force acting on the log. We have two forces:

- The constant pulling force, forward, of F = 2500 N

- The frictional force, backward

The frictional force is given by

$F_f = \mu mg$

where

$\mu=0.45$ is the coefficient of friction

m = 300 kg is the mass of the log

$g=9.8 m/s^2$ is the acceleration of gravity

Substituting,

$F_f = (0.45)(300)(9.8)=1323 N$

So the net force acting on the log is

$F=2500 - 1323=1177 N$

Now, we can find the acceleration of the log by using Newton's second law

$F=ma$

where a is the acceleration. Re-arranging for a,

$a=\frac{F}{m}=\frac{1177}{300}=3.92 m/s^2$

And finally we can find the time it takes for the log to reach a speed of

v = 0.5 m/s

by using the suvat equation:

$v=u+at$

where u = 0 is the initial speed and t the time. Solving for t,

$t=\frac{v}{a}=\frac{0.5}{3.92}=0.128 s$

5 0

4 years ago

Which of one example of pre-existing marine life?

Mekhanik [1.2K]

B. a shrimp burrow cause A,C,D is above the sea/ocean

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3 years ago

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How are fossil fuels formed

KATRIN_1 [288]

It is formed by decayed animals and plants

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3 years ago

Which of the following is the equation for gravitational potential energy?

andrezito [222]

B is momentum. It's a quantity of motion, or "how much stuff is moving"

C is *almost* kinetic energy but it's missing an exponent of 2 on the velocity, v.

D is an amound of work done in moving something a distance d while applying a constant force F.

That leaves A. This is the potential energy of an object of mass m, in a gravitational acceleration g, at a height h above the reference point (usually the ground)

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3 years ago

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