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3 years ago

The standard unit of work in the metric system is named after the scientist _____.

Physics

2 answers:

Lena [83]3 years ago

7 0

James Prescott Joule (1818 - 1889)

Harlamova29_29 [7]3 years ago

4 0

Answer: Hello there! The standard unit of work in the metric system, the joule, is named after the James Prescott Joule (1819 -1889), where a joule is $j = \frac{kg*m}{s^{2} }$ . He was a physicist who did a lot of work with thermodynamics, for example, he worked on the Joule-Thomson effect.

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A sled slides along a horizontal surface on which the coefficient of kinetic friction is 0.25. Its velocity at point A is 8.4 m/

Bad White [126]

Answer:

1.06 secs

Explanation:

Initial speed of sled, u = 8.4 m/s

Final speed of sled, v = 5.8 m/s

Coefficient of kinetic friction, μ = 0.25

Using the impulse momentum theory, we know that the impulse applied to the sled is equal to change in momentum of the sled:

FΔt = mv - mu

where m = mass of the object

Δt = time interval

F = force applied

The force applied on the sled is the frictional force, which is given as:

F = -μmg

where g = acceleration due to gravity

Therefore:

-μmgΔt = mv - mu

-μmgΔt = m(v - u)

-μgΔt = v - u

Making Δt subject of formula:

Δt = (v - u) / -μg

Δt = (5.8 - 8.4) / (-0.25 * 9.8)

Δt = -2.6/ -2.45

Δt = 1.06 secs

It took the sled 1.06 secs to travel from A to B.

7 0

3 years ago

two punds of water vapor at 30 psia fill the 4ft3 left chmaber of a partitioned system. The right chmaber has twice the volume o

tamaranim1 [39]

Answer:

pressure of water will be 49.7 atm

Explanation:

given data

pressure = 30 psi = 2.04 atm

water = 2 pound = 907.18

mole of water vapor = 907.19 /2 = 50.4 mole

volume = 4 ft³ = 113.2 L

temperature = 40 F = 277.59 K

to find out

pressure of water

solution

we will apply here ideal gas condition

that is

PV = nRT .......................1

put here all value and here R = 0.0821 , T temperature and V volume and P pressure and n is no of mole

and we get here temperature

PV = nRT

2.04 × 113.2 = 50.4×0.0821×T

solve it and we get

T = 55.8 K

so we have given right chamber has twice the volume of the left chamber i.e

volume = twice of volume + volume

volume = 2(113.2) + 113.2

volume = 339.6 L

so from equation 1 pressure will be

PV = nRT

P(339.6) = 50.4 × ( 0.0821) × (277.59)

P = 3.3822 atm = 49.7 atm

so pressure of water will be 49.7 atm

7 0

3 years ago

If you drag a sled on the ground, what does the sled experience?

Ilya [14]

The sled experiences friction against the ground

3 0

3 years ago

Vector A??? has a magnitude of 2.00 m and vector B??? has a magnitude of 5.00 m. If the direction of each vector is unknown, wha

masya89 [10]

If the two vectors decide to work together, practice teamwork
and cooperation, and both push in exactly the same direction,
then they can team up to make a single vector of (2m + 5m) = 7m .

8 0

3 years ago

Wind instruments like trumpets and saxophones work on the same principle as the "tube closed on one end" that we examined in our

Gnom [1K]

Answer:

f = v / 4L

the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.

Explanation:

In wind instruments the wave speed must meet

v = λ f

λ = v / f

from v is the speed of sound that depends on the temperature

v = v₀ $\sqrt{1+ \frac{T [C]}{273} }$

where I saw the speed of sound at 0ºC v₀ = 331 m/s the temperature is in degrees centigrade, we can take the degrees Fahrenheit to centigrade with the relation

(F -32) 5/9 = C

76ºF = 24.4ºC

45ºF = 7.2ºC

With this relationship we can see that the speed of sound is significantly reduced when leaving the house to the outside

at T₁ = 24ºC v₁ = 342.9 m / s

at T₂ = 7ºC v₂ = 339.7 m / s

To satisfy this speed the wavelength of the sound must be reduced, so the resonant frequencies change

λ / 4 = L

λ= 4L

v / f = 4L

f = v / 4L

Therefore, the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.

3 0

3 years ago