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2 years ago

PLZ HELP ME

2 answers:

3 0

CRASHES trip sensors in cars that send an electric signal to an ignitor. The heat generated causes sodium azide to decompose into sodium metal and nitrogen gas, which inflates the car's air bags. ... A handful (130 grams) of sodium azide will produce 67 liters of nitrogen gas--which is enough toinflate a normal air bag.

Lilit [14]2 years ago

3 0

A. The added gas increases the pressure and then the volume of the air bag

Note: the added gas is nitrogen

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Compute the kinetic energy of a proton (mass 1.67×10−27kg ) using both the nonrelativistic and relativistic expressions for spee

JulsSmile [24]

Answer:

The non-relativistic kinetic energy of a proton is $6.76\times10^{-12}\ J$

The relativistic kinetic energy of a proton is $7.25\times10^{-12}\ m/s$

Explanation:

Given that,

Mass of proton $m=1.67\times10^{-27}\ kg$

Speed $v= 9.00\times10^{7}\ m/s$

We need to calculate the kinetic energy for non relativistic

Using formula of kinetic energy

$K.E=\dfrac{1}{2}mv^2$

Put the value into the formula

$K.E=\dfrac{1}{2}\times1.67\times10^{-27}\times(9.00\times10^{7})^2$

$K.E=6.76\times10^{-12}\ J$

We need to calculate the kinetic energy for relativistic

Using formula of kinetic energy

$K.E=mc^2(\sqrt{(\dfrac{1}{1-\dfrac{v^2}{c^2}})}-1)$

$K.E=1.67\times10^{-27}\times(3\times10^{8})^{2}\cdot\left(\sqrt{\frac{1}{1-\frac{\left(9.00\times10^{7}\right)^{2}}{(3\times10^{8})^{2}}}}-1\right)$

$K.E=7.25\times10^{-12}\ m/s$

Hence, The non-relativistic kinetic energy of a proton is $6.76\times10^{-12}\ J$

The relativistic kinetic energy of a proton is $7.25\times10^{-12}\ m/s$

7 0

3 years ago

SHOW WORK

Helga [31]

Answer:

Follows are the solution to the given question:

Explanation:

For point a:

$T= 2\pi \sqrt{\frac{m}{k}}\\\\k = \frac{4 \pi^2 m}{T^2}\\\\= \frac{4 \times (3.14)^2 \times 3}{2^2}\\\\=29.578 \ \frac{N}{m}\\\\$

For Point b:

$E=\frac{1}{2} m a^2 w^2\\\\$

$=\frac{1}{2} \times m \times a^2 \times \frac{4\pi^2}{T^2}\\\\=\frac{1}{2} \times 3 \times (0.15)^2 \times \frac{4\times 3.14^2}{2^2}\\\\=0.332 \ J$

For Point C:

$V_{max}= a w$

$= (0.15) \times \frac{2\pi}{T}\\\\= (0.15) \times \frac{2\times 3.14}{2}\\\\=0.471 \frac{m}{s}$

For point D:

$X= a \sin (wt+ \phi)\\\\0.91=0.15 \sin(\frac{2\pi}{T} \times t+\phi)\\\\0.91=0.15 \sin(\frac{2\times 3.14}{2} \times 0.5+\phi)\\\\0.60 = \sin(3.14 \times 0.5+\phi)\\\\0.60 = \sin(1.57+\phi)\\\\1.57 +\phi =\sin^{-1} 60^{\circ}\\\\1.57 +\phi = 36.86^{\circ}\\\\=35.29^{\circ}\\\\So, X=15 \sin(3.14t+35.29^{\circ}) \ cm$

5 0

3 years ago

What are the positive impacts of Genetically Modified Crops?

xeze [42]

Answer:

The crops will have the ability to be resistant to certain diseases

7 0

2 years ago

Read 2 more answers

A proton in a cyclotron is moving with a speed of 2.97×107 m/s in a circle of radius 0.568 m. 1.67 × 10−27 kg is the mass of the

vivado [14]

Answer:

B = 0.546 T, F = 2.59 10⁻¹² N

Explanation:

The magnetic force is

F = q v x B

We can calculate the magnitude of the force and find the direction by the right hand rule

F = q v B sin θ

Let's use Newton's second law

F = m a

Acceleration is centripetal

a = v² / r

We substitute

q v B sin θ = m v² / r

The angle between the field and the radius of the circle is 90º so sin 90 = 1

q B = m v / r

B = m v / q r

Let's calculate ’

B = 1.67 10⁻²⁷ 2.97 10⁷ / (1.60 10⁻¹⁹ 0.568)

B = 0.546 T

The foce is

F = q v B

F = 1.60 10⁻¹⁹ 2.97 10⁷ 0.546

F = 2.59 10⁻¹² N

3 0

3 years ago

When an electron is added to a neutral atom of an element to form a negative ion, the resulting change in energy is referred to

IgorLugansk [536]

The statement "When an electron is added to a neutral atom of an element to form a negative ion, the resulting change in energy is referred to as the electron potential of that element." is false.

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

4 0

3 years ago