No. I Is actually V/R. R/V would be 1/I.
Answer:
15 KJ
Explanation:
The quantity of heat (Q) required is given as:
Q = mcΔθ + mL
where m is the mass of ice, c is its specific heat capacity, L is its specific latent heat andΔθ is the change in temperature.
Given: m = 20g, temperature of ice = 0
, specific heat capacity of water = 4200 J/kg, latent heat of fusion of ice = 3.3 x 10^(5) J/kg, temperature of water = 100.
Q = m (cΔθ + L)
= 0.02(4200 x (100) + 330000)
= 0.02(420000 + 330000)
= 0.02 (750000)
Q = 15000
Q = 15000 Joules
Q = 15KJ
The quantity of heat needed to complete the conversion is 15 KJ.
Answer:
one-third of its weight on Earth's surface
Explanation:
Weight of an object is = W = m*g
Gravity on Earth = g₁ = 9.8 m/s
Gravity on Mars = g₂ = 
g₁
Weight of probe on earth = w₁ = m * g₁
Weight of probe on Mars = w₂ = m * g₂ -------- ( 1 )
As g₂ = g₁/3 --------- ( 2 )
Put equation (2) in equation (1)
so
Weight of probe on Mars = w₂ = m * g₁ /3
Weight of probe on Mars = m * g₁ = w₁
⇒Weight of probe on Mars = Weight of probe on earth
Answer:
ΔE = GMm/24R
Explanation:
centripetal acceleration a = V^2 / R = 2T/mr
T= kinetic energy
m= mass of satellite, r= radius of earth
= gravitational acceleration = GM / r^2
Now, solving for the kinetic energy:
T = GMm / 2r = -1/2 U,
where U is the potential energy
So the total energy is:
E = T+U = -GMm / 2r
Now we want to find the energy difference as r goes from one orbital radius to another:
ΔE = GMm/2 (1/R_1 - 1/R_2)
So in this case, R_1 is 3R (planet's radius + orbital altitude) and R_2 is 4R
ΔE = GMm/2R (1/3 - 1/4)
ΔE = GMm/24R
Answer: C. Some of uranium's mass is converted into energy, so the smaller atoms have less mass.
Explanation:
From Einstein's mass-energy relation:
E = mc²
Mass and energy are equivalent. Mass can be converted into energy and energy into mass.
When Uranium atoms under go nuclear fission, smaller atoms are formed and huge amount of energy is released. This energy comes from the mass difference of the uranium nuclei and new nuclei formed. This mass converted into energy according to Einstein's equation.
