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Genrish500 [490]
3 years ago
7

HELP I AM TIMED PLZZZZZZ!!!!!!!!!!!!!!!

Mathematics
1 answer:
otez555 [7]3 years ago
3 0

Answer:

2/6 = d/84 d=24

Step-by-step explanation:

d=24

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Alan made a small four sided table for his office .Two sides of the table are 27 inches long and 36 inches long .If the diagonal
Tcecarenko [31]

Answer:

does NOT have right angles at the corners

Step-by-step explanation:

we are given that the sides of a table are 27" and 36" long.

If we assume the table to be rectangular, then by Pythagorean formula, we can find the diagonal and compare it to the 40" that we are given.

(refer to attached)

diagonal² = 27² + 36²

diagonal² = 27² + 36²

diagonal² = 2025

diagonal = √2025

diagonal = 45 inches

because the diagonal that we found is not the same as the 40" that was given, we can conclude that the table is not a rectangle (i.e does not have right angles at the corners)

6 0
3 years ago
A new crew of painters can paint a small apartment in 12 hours. an experienced crew can paint the small apartment in 6 hours. ho
Yakvenalex [24]
This is the concept of proportionality, we are required to calculate for the number of hours two crews can use to paint the house altogether.
Here proceed as follows;
number of hours new crew can paint=12 hrs
portion of work painted by new crew in 1 hour= 1/12

number of hours experienced crew can paint=6 hours
Portion of work painted by experienced crew in 1 hour=1/6

Portion of work painted by the two crews altogether in 1 hour will be:
1/6+1/12=1/4

thus the total amount of hours that the two painters will take to paint will be:
4 hours


6 0
3 years ago
Assume that a random sample of 4 Goldfinch birds are going to be used to test the above hypothesis. Compute the largest value of
Misha Larkins [42]

This question is incomplete, the complete question is;

Assume that body masses of Goldfinch birds follow a normal distribution, with a standard deviation equal to 0.04 oz. An ornithologist who would like to make some inference about the average body mass of the Goldfinch birds. In particular, at a significance level of 0.01, she would like to test the null hypothesis H₀: Average body mass of the Goldfinch birds is 0.5 oz, against the alternative claim that average body size is less than 0.5 oz.

      Assume that a random sample of 4 Goldfinch birds are going to be used to test the above hypothesis. Compute the largest value of the sample mean, that will allow the experimenter reject the null and prove the alternative at significance level 0.01. For this problem, make sure that your solution includes all steps of your computation. You will not earn points if you just use a formula

Answer: the largest value of the sample mean that will enable the experimenter to reject the null hypothesis is 0.4534 oz.

Step-by-step explanation:

Let us consider testing a hypothesis about a population mean with population standard deviation that is known,

Let the average body mass of the Goldfinch bird be μ^μ

Now our hypotheses are will be;

H₀ : μ = 0.5    and

H₁ : μ < 0.5

For the test, we shall use the z statistic which will be

z = (x"-μ)/(σ/√n)

Now given that;

σ = 0.04 and n = 4  

sample mean x" = ?

Now in order to be able to reject the null hypothesis, the p-value should be ≤ α = 0.01.

so to find the largest value of sample mean, we will use the maximum of p-value that is 0.01.

For a p-value = 0.01 at the lower tail (which is the percentile for z),

the corresponding z will be -2.33

so we substitute our values into our formula

z = (x"-μ)/(σ/√n)

z(σ/√n) = (x"-μ)

-2.33(0.04/√n) = (x"-0.5)

-0.0466 = x" - 0.5

x" = 0.5 - 0.0466

x"= 0.4534

therefore the largest value of the sample mean that will enable the experimenter to reject the null hypothesis is 0.4534 oz.

4 0
3 years ago
I need help on number 23 and explain please for brainiest answer !!
Leviafan [203]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Experimental probability is the same as empirical probability and relative frequency.
BlackZzzverrR [31]
If this is a true or false question, then the answer would be true. It is correct that the three terms mentioned are the same. Experimental and empirical probability can be interchanged or even synonymous with one another, as well as relative frequency (or frequency ratio). 
3 0
3 years ago
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