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Genrish500 [490]
3 years ago
7

HELP I AM TIMED PLZZZZZZ!!!!!!!!!!!!!!!

Mathematics
1 answer:
otez555 [7]3 years ago
3 0

Answer:

2/6 = d/84 d=24

Step-by-step explanation:

d=24

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PLEASE ANSWER AND EXPLAIN | 98 POINTS
DIA [1.3K]

Answer:

Step-by-step explanation:

R-value can range from -1 to 1 with correlation being strongest at -1 and 1 and weakest at 0.

So the answer is D. -0.9.

3 0
3 years ago
Read 2 more answers
Una caja de 25 newtons se suspende mediante un cable con diámetro de 2cm¿cuál es el esfuerzo aplicado al cable?
Naddik [55]

El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.

<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:

σ = W / (π · D² / 4)

Donde:

  • W - Peso de la caja, en newtons.
  • D - Diámetro del área transversal de la caja, en metros.

Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:

σ = 25 N / [π · (0.02 m)² / 4]

σ ≈ 79577.472 Pa

<h3>Observación</h3>

La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145

#SPJ1

5 0
1 year ago
69) Half-way to the center of a planet of uniform density, your weight compared to that at the surface would be :
mel-nik [20]

Answer:

One- half

Step-by-step explanation:

Since the density is uniform  

Mass of the sphere = [(4/3) π r^3] d

where d is the uniform density.

Mass of the sphere = [(4/3) π d] r^3 = k r^3

where k = [(4/3) π d] is a constant  

Weight = mg = G m M / r^2 = G m [k r^3] /r^2 = G m k r

Using Gauss’ law for gravitation,

Half way to the center of a planet the weight is only due to the inner sphere and the outer sphere does not contribute to his weight,  

Inside his weight is mg’ = (G m k  r) /2   = mg/2  

Answer is one-half.

7 0
3 years ago
Consider parallelogram ABCD. Which of the following transformations will change the perimeter of the parallelogram?
jeka57 [31]

In geometry, transformation involves changing the position and/or size of a shape.

<em>The transformation that will change the size of ABCD is dilation.</em>

There are four transformations in geometry:

  • Translation
  • Reflection
  • Rotation
  • Dilation

Of all types of transformation, dilation will change the size of the shape,

The new shape will either be enlarged or reduced

<em>Either ways, the size of the shape will be altered.</em>

<em>When the size is altered, the perimeter will not remain the same.</em>

<em />

Hence. dilation will change the perimeter of ABCD.

Read more about transformations at:

brainly.com/question/11709244

4 0
2 years ago
Find x and y in the following figure
Ipatiy [6.2K]

Y=145, I’m not sure about X

6 0
3 years ago
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