Answer:
80
Step-by-step explanation:
-4,-1,2,5,8,11,14,17,20,23,26,29,32,35,38,41,44,47,50,53,56,59,62,65,68,71,74,77,80.
C. y₂ = (1 + (t/n))²
yₙ₊₁ = yₙ + Δt F(tₙ, yₙ)
yₙ₊₁ = yₙ + Δt yₙ
yₙ₊₁ = yₙ + (t/n) yₙ
When n=0:
y₁ = y₀ + (t/n) y₀
y₁ = 1 + (t/n)
When n=1:
y₂ = y₁ + (t/n) y₁
y₂ = 1 + (t/n) + (t/n) (1 + (t/n))
y₂ = 1 + (t/n) + (t/n) + (t/n)²
y₂ = 1 + 2(t/n) + (t/n)²
y₂ = (1 + (t/n))²
15
The second one
Your one is the correct
28-8 is the answer simplified but not yet complete
20 is the final answer
Hope this helps :)
Answer: Yes, (2,1) is a solution.
Point for : (2,1)
Equation form : x=2 , y=1
Step-by-step explanation: Solve for the first variable in one of the equations, then substitute the result into the other equation.
Hope this helps you out! ☺
