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2 years ago

What is the 30th term of the linear sequence below? -4,-1,2,5,8...

Mathematics

1 answer:

Airida [17]2 years ago

7 0

Answer:

Step-by-step explanation:

-4,-1,2,5,8,11,14,17,20,23,26,29,32,35,38,41,44,47,50,53,56,59,62,65,68,71,74,77,80.

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Which equation is equivalent to<br> y-1= 5(x+2) ?

Agata [3.3K]

Step-by-step explanation:

We can simply by opening the brackets ,

=> y - 1 = 5( x - 2 )

=> y - 1 = 5x - 10

=> y - 5x = -9

=> 5x - y + 9 = 0

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2 years ago

Which polygon in the diagram cannot be mapped onto the others by similarity transformations?

Rom4ik [11]

Answer: B.) PQRST

Step-by-step explanation:

There are no options but if its the same question I just had on a test then this is the answer..

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2 years ago

How many years is 694.44 days?

antoniya [11.8K]

Answer:

1.9 years

Step-by-step explanation:

There are 365 days in a year

694.44 / 365 = 1.9

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2 years ago

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I need help with homework

FromTheMoon [43]

Answer:

Step-by-step explanation:

Point C is on the x-axis.

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2 years ago

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Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

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2 years ago

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