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Alik [6]
3 years ago
11

7/3 Lithium. Protons, NEUTRONS & Electrons

Chemistry
1 answer:
LiRa [457]3 years ago
8 0

Answer:

With positive ions these will have fewer electrons than protons, making them positive. With negative ions these will have more electrons than protons, making them negative. Lithium atom has electron arrangement 2,1 and the Li+ ion will be 2. So 7/3 Li+ has 3 protons, 4 neutrons and 2 electrons

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The gases carbon dioxide, oxygen, and argon are mixed in a container. All gases have the same partial pressure, and the total pr
polet [3.4K]
The partial pressure of argon can be calculated simply by dividing the total pressure by 3. This gives an answer equivalent to 10893.33 Pa. The clue behind this is the statement "a<span>ll gases have the same partial pressure". This follows Dalton's Law of Partial Pressures which states that the total pressure is equal to the sum of the individual partial pressures.</span>
4 0
3 years ago
A discus thrower throws a 1.6kg discus at 25m/s what's the kinetic energy?​
Ilya [14]

Answer:

<h2>500 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2} \\

where

m is the mass

v is the velocity

From the question

m = 1.6 kg

v = 25 m/s

We have

k =  \frac{1}{2}  \times 1.6 \times  {25}^{2}  \\  = 0.8 \times 625 \\  = 500

We have the final answer as

<h3>500 J </h3>

Hope this helps you

6 0
3 years ago
Which of the following instrument would you use to see a plant cell?
Gemiola [76]
B . microscope
this is the answer .
3 0
2 years ago
Read 2 more answers
A 48.3 mL sample of gas in a cylinder is warmed from 22 C, 87 C to 0.0 C what is the final temperature
snow_lady [41]

The answer is:

the volume stays the same. it is the pressure that increases

7 0
3 years ago
"How much NH4Cl, when present in 2.00 liters of 0.200 M ammonia, will give a solution with pH = 8.20? For NH3, Kb = 1.8 x 10-5"
Andru [333]

Answer:

245.66g of NH₄Cl is the mass we need to add to obtain the desire pH

Explanation:

The mixture of NH3/NH4Cl produce a buffer. We can find the pH of a buffer using H-H equation:

pH = pKa + log [A⁻] / [HA]

<em>Where [A⁻] is the molar concentration of the base, NH₃, and [HA] molar concentration of the acid, NH₄⁺. This molar concentration can be taken as the moles of each chemical</em>

<em />

First, we need to find pKa of NH₃ using Kb. Then, the moles of NH₃ and finally replace these values in H-H equation to solve moles of NH₄Cl we need to obtain the desire pH.

  • <em>pKa NH₃/NH₄⁺</em>

pKb = - log Kb

pKb = -log 1.8x10⁻⁵ = <em>4.74</em>

pKa = 14 - pKb

pKa = 14 - 4.74

pKa = 9.26

  • <em>Moles NH₃</em>

<em>2.00L ₓ (0.200mol NH₃ / L) = 0.400 moles NH₃</em>

  • <em>H-H equation:</em>

pH = pKa + log [NH₃] / [NH₄Cl]

8.20 = 9.26 + log [0.400 moles] / [NH₄Cl]

-1.06 =  log [0.400 moles] / [NH₄Cl]

0.0087 =  [0.400 moles] / [NH₄Cl]

[NH₄Cl] = 0.400 moles / 0.0087

[NH₄Cl] = 4.59 moles of NH₄Cl we need to add to original solution to obtain a pH of 8.20. In grams (Using molar mass NH₄Cl=53.491g/mol):

4.59 moles NH₄Cl ₓ (53.491g / mol) =

<h3>245.66g of NH₄Cl is the mass we need to add to obtain the desire pH</h3>

<em />

3 0
3 years ago
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