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Schach [20]
3 years ago
15

Who knows how to do this please help

Chemistry
1 answer:
Fofino [41]3 years ago
5 0

Answer: You forgot to zero the balance

Explanation:

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A stock solution of sodium sulfate NaSO4 has a concentrate of 1.00 m. The volume of this solution is 50 ml. What volume of 0.25
mylen [45]
<h3>Answer:</h3>

200 mL

<h3>Explanation:</h3>

Concept tested: Dilution formula

We are given;

  • Concentration of stock solution as 1.00 M
  • Volume of the stock solution as 50 mL
  • Molarity of the dilute solution as 0.25 M

We are required to calculate the volume of diluted solution;

  • The stock solution is the original solution before dilution while diluted solution is the solution after dilution.
  • Using the dilution formula we can determine the volume of diluted solution;

M1V1 = M2V2

Rearranging the formula;

V2 = M1V1 ÷ M2

     = (1.00 M × 50 mL) ÷ 0.25 M

     = 200 mL

Therefore, a volume of 200mL of 0.25 M solution could be made from the stock solution.

5 0
3 years ago
Determine the molar mass for ammonia (NH3) in g/mol.
navik [9.2K]

Answer:

17.031 g/mol

Explanation:

5 0
3 years ago
Identify the standard metal cations in the active components of soaps
rjkz [21]
Answer is: standard metal cations are sodium cation (Na⁺), potassium cation (K⁺), magnesium cation (Mg²⁺) and calcium cation (Ca²⁺).
Soap<span> is a </span>salt<span> of a </span>fatty acid. When soap have sodium and potassim cations, that is toilet soap and when soap have magnesium and calcium cations, that soap is called <span>metallic soap.</span>
8 0
4 years ago
A published hypothesis:
Yuki888 [10]
2) Should be tested by the scientific community
3 0
3 years ago
What is the log of 1 x 10^23?
Degger [83]

Answer:

23 is the log of 1 x 10^{23} .

Explanation:

x=\log 1\times 10^{23}

\log (ab)=\log a+ \log b

x=\log 1+\log 10^{23}

\log a^b=b\log a

x = \log 1 +23\log 10

x=23

23 is the log of 1 x 10^{23} .

5 0
3 years ago
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