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olasank [31]
3 years ago
7

A clear liquid in an open container is allowed to evaporate. after three days a solid residue is left. was the original liquid a

n element, compound, or mixture? how do you know?
Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
8 0

The clear liquid was allowed to evaporate and after 3 days, only solids are left. Therefore this means that for the 3 days it was exposed to air, some liquid or water perhaps was leaving out of the solution. Therefore this means that the liquid was a mixture. It was a initially a mixture of the solid residue plus the evaporated liquid.

It cannot be an element or a compound since both uniformly evaporates.

 

Answer:

<span>Mixture</span>

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What volume (mL) of 0.135 M NaOH is required to neutralize 13.7 mL of 0.129 M HCl? a: 0.24 b: 13.1 c: 0.076 d: 6.55 e: 14.3
Len [333]

Answer:

The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).

Explanation:

The reaction between an acid and a base is called neutralization, forming a salt and water.

Salt is an ionic compound made up of an anion (positively charged ion) from the base and a cation (negatively charged ion) from the acid.

When an acid is neutralized, the amount of base added must equal the amount of acid initially present. This base quantity is said to be the equivalent quantity. In other words, at the equivalence point the stoichiometry of the reaction is exactly fulfilled (there are no limiting or excess reagents), therefore the numbers of moles of both will be in stoichiometric relationship. So:

V acid *M acid = V base *M base

where V represents the volume of solution and M the molar concentration of said solution.

In this case:

  • V acid= 13.7 mL= 0.0137 L (being 1,000 mL= 1 L)
  • M acid= 0.129 M
  • V base= ?
  • M base= 0.135 M

Replacing:

0.0137 L* 0.129 M= V base* 0.135 M

Solving:

V base=\frac{0.0137 L*0.129 M}{0.135 M}

V base=0.0131 L = 13.1 mL

<u><em> The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).</em></u>

4 0
3 years ago
Consider the oxidation of sodium metal to sodium oxide described by the balanced equation:
mixas84 [53]

Answer:

1116 g.

Explanation:

The balanced equation for the reaction is given below:

4Na + O₂ —> 2Na₂O

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of Na₂O.

Next, we shall determine the theoretical yield of Na₂O. This can be obtained as follow:

From the balanced equation above,

1 mole of O₂ reacted to produce 2 moles of Na₂O.

Therefore, 9 moles of O₂ will react to produce = 9 × 2 = 18 moles of Na₂O.

Finally, we shall determine the mass in 18 moles of Na₂O. This can be obtained as follow:

Mole of Na₂O = 18 moles

Molar mass of Na₂O = (23×2) + 16

= 46 + 16

= 62 g/mol

Mass of Na₂O =?

Mass = mole × molar mass

Mass of Na₂O = 18 × 62

Mass of Na₂O = 1116 g

Thus, the theoretical yield of Na₂O is 1116 g.

3 0
2 years ago
Make the following conversion. 120 mL = _____ cm³ <br><br> 12.0<br> 1200<br> 120<br> 1.20
Lina20 [59]
The correct answer would be 120.
4 0
3 years ago
Read 2 more answers
A truck is moving at the rate of 40 km/hr. How far does it move when it stops after 5 seconds?
seraphim [82]
First of all, this is the chemistry section, while your question is a physics question. Anyway I'll tell you how to solve it.

First we need to find the rate that the truck moves in a second.

1km = 1000m
40km = 40000m
40000m/hr
1 hour = 60 minutes
40000m/hr ÷ 60 = 666.66(repeating)/minute
1 minute = 60 seconds
666.66m/min ÷ 60 = 11.11(rep)m/s

Next we simply multiply the speed of the truck by the number of seconds it travels.

11.11 × 5 = 55.55
Make sure to round it unless you indicate the repeating decimal.
The truck moved 55.56m in 5 seconds.
6 0
3 years ago
the sublevel that has the largest number of differently shaped orbitals is the f sublevel. True False
GrogVix [38]

The answer to this is true.

5 0
3 years ago
Read 2 more answers
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