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olasank [31]
3 years ago
7

A clear liquid in an open container is allowed to evaporate. after three days a solid residue is left. was the original liquid a

n element, compound, or mixture? how do you know?
Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
8 0

The clear liquid was allowed to evaporate and after 3 days, only solids are left. Therefore this means that for the 3 days it was exposed to air, some liquid or water perhaps was leaving out of the solution. Therefore this means that the liquid was a mixture. It was a initially a mixture of the solid residue plus the evaporated liquid.

It cannot be an element or a compound since both uniformly evaporates.

 

Answer:

<span>Mixture</span>

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What did Bohr’s model focus on that Rutherford’s model did not?
wlad13 [49]

Answer:

Because Rutherford's model was weak on the position of the electrons, Bohr focused on them. He hypothesized that electrons can move around the nucleus only at fixed distances from the nucleus based on the amount of energy they have. ... However, an electron could never exist in between two energy levels

3 0
3 years ago
What does the symbol H stand for
muminat

Answer:

enthalpy

Explanation:

If it is used with a triangle in front, (delta H), that means the change in enthalpy. Delta H= (m)(s)(Delta T).  m=mass of products, s=heat of the products, Delta T = change in temperature.

Hope that helps

4 0
3 years ago
Examine the models shown above.where is potential energy the greatest
Lisa [10]

Answer:

A

Explanation:

Because it is the greatest

7 0
3 years ago
6. What is the wavelength (in meters) of the electromagnetic carrier wave transmitted by The Sports
Vsevolod [243]

Answer:

wavelength = 2.81 m

Explanation:

Given that,

The frequency of the Sports  Fan radio station, f = 106.4 MHz

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c=f\lambda

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\lambda is wavelength

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{106.4\times 10^6}\\\\\lambda=2.81\ m

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8 0
3 years ago
Choose the covalent compounds from the following choices Br2 MgS SO2 KF
Novosadov [1.4K]

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

 

                Less than 0.4 then it is Non Polar Covalent Bond

                

                Between 0.4 and 1.7 then it is Polar Covalent Bond

            

                Greater than 1.7 then it is Ionic

 

For Br₂;

                    E.N of Bromine      =   2.96

                    E.N of Bromine      =   2.96

                                                   ________

                    E.N Difference             0.00          (Non Polar Covalent Bond)


For MgS;

                    E.N of Sulfur               =   2.58

                    E.N of Magnesium      =   1.31

                                                   ________

                    E.N Difference                  1.27          (Ionic Bond)


For SO₂;

                    E.N of Oxygen      =   3.44

                    E.N of Sulfur          =   2.58

                                                   ________

                    E.N Difference             0.86          (Polar Covalent Bond)


For KF;

                    E.N of Fluorine          =   3.98

                    E.N of Potassium      =   0.82

                                                   ________

                    E.N Difference                3.16          (Ionic Bond)

Result: The Bonds in Br₂ and SO₂ are Covalent in Nature.

3 0
3 years ago
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