The acceleration of the car is 0.5 meters per seconds square.
Given the following data:
- Initial velocity, U = 30 m/s
Note: The final velocity (V) of the car would be zero (0) m/s when it comes to a stop.
To find the acceleration of the car, we would use the third equation of motion;
Mathematically, the third equation of motion is given by the formula;

<em>Acceleration, a </em><em>=</em><em> 0.5 </em>
<em></em>
Therefore, the acceleration of the car is 0.5 meters per seconds square.
Read more: brainly.com/question/8898885
The formula for the speeder should beV1 = d1/t1whereas the formula for the police car is d2 = vo t2 + 1/2 at2^2 where a is equal to 2.44 m/s2. when the overtaking takes place, d1 and d2 are the same, so as t1 and t2
30t = 1/2 *2.44*t2t is equal to 24.59 seconds.d then is equal to 737.70 meters
<span>The answer is 15 centimeters. The waves with the
smallest wavelengths (also highest
frequency) have the least capacity to diffract around objects hence have a
shadowing effect, behind the object, especially if the wavelength is small
compared to the object. This is also the reason why high-frequency electromagnetic waves do not have a good reach in mountainous
regions. </span>