All categories

3 years ago

5. A student is investigating the relationship between pressure,

Physics

1 answer:

sergey [27]3 years ago

4 0

Answer:

The water vapor will have the greatest entropy at the triple point

Explanation:

At the triple point of water, which has the properties of 0.0075°C temperature and 6.11657 mbar pressure, solid ice, liquid water and water vapor exist together in a location

According to Professor Stephen Lower on LibreTexts website entropy is a measure the extent to which thermal energy is shared and spread in a system

The change in entropy, ΔS = ΔH/T

The heat change in $\Delta H_{melting}$ = 6.01 kJ/mol

The heat change in vaporization, $\Delta H_{vaporization}$ = 45.05 kJ/mol

The heat change in sublimation, $\Delta H_{sublimation}$ = 51.06 kJ/mol

Therefore, the entropy of the water vapor $S_{water \ vapor}}$ > The entropy of liquid water, $S_{Liquid \ water}$ > The entropy of the solid ice, $S_{Solid \, ice}$

The portion with the highest entropy at the triple point is the water vapor

The water vapor will have the greatest entropy at the triple point

You might be interested in

Length of table is 1.0m,1.00m and 1.000m.Which one is more accurate?

natita [175]

Answer:

1.00 m is a more accurate measured length.

Explanation:

Denote length of the table by L.

For L=1.0 m, there is one significant digit after the decimal.

Care 1: When one more significant digit after decimal considered, the exact number can be from 0.95 to 1.05.

So, the possible span of error $\Delta E_1= 1.05-0.95= 0.1m$

For L=1.00 m, there is two significant digits after the decimal.

Case 2: When one more significant digit after decimal considered, the exact number can be from 0.095 to 1.005.

So, the possible span of error $\Delta E_2= 1.005-0.095= 0.01m$

Case 3: For L=1.000 m, there is three significant digits after the decimal.

When one more significant digit after decimal considered, the exact number can be from 0.0095 to 1.0005.

So, the possible span of error $\Delta E_3= 1.0005-0.0095= 0.001m$

As $\Delta E_1 >\Delta E_2>\Delta E_3$

So, the least error is in the third case when L=1.00m, hence, L= 1.00m is more accurate.

6 0

3 years ago

Calculate the wavelengths of the first five members of the Lyman series of spectral lines, providing the result in units Angstro

Oduvanchick [21]

Answer:

Explanation:

The formula for hydrogen atomic spectrum is as follows

energy of photon due to transition from higher orbit n₂ to n₁

$E=13.6 (\frac{1}{n_1^2 } - \frac{1}{n_2^2})eV$

For layman series n₁ = 1 and n₂ = 2 , 3 , 4 , ... etc

energy of first line

$E_1=13.6 (\frac{1}{1^2 } - \frac{1}{2 ^2})$

10.2 eV

wavelength of photon = 12375 / 10.2 = 1213.2 A

energy of 2 nd line

$E_2=13.6 (\frac{1}{1^2 } - \frac{1}{3 ^2})$

= 12.08 eV

wavelength of photon = 12375 / 12.08 = 1024.4 A

energy of third line

$E_3=13.6 (\frac{1}{1^2 } - \frac{1}{4 ^2})$

12.75 e V

wavelength of photon = 12375 / 12.75 = 970.6 A

energy of fourth line

$E_4=13.6 (\frac{1}{1^2 } - \frac{1}{5 ^2})$

= 13.056 eV

wavelength of photon = 12375 / 13.05 = 948.3 A

energy of fifth line

$E_5=13.6 (\frac{1}{1^2 } - \frac{1}{6 ^2})$

13.22 eV

wavelength of photon = 12375 / 13.22 = 936.1 A

7 0

3 years ago

If your front lawn is 18.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1050 new snow flakes every min

Ivanshal [37]

First, we need to determine the entire area of your front line by multiplying its length times its width.
18.0*20.0 = 360.0 square feet
We can use the rate of accumulation of snow, combined with this figure, to determine how much snow accumulates on your lawn per minute.
360.0 sq ft * 1050 flakes/min/sq ft = 378,000 flakes/min
We can then use the mass of a snowflake to calculate total snow accumulation per minute.
378,000 flakes/min * 2.00 mg/flake = 756,000 mg/min
Finally, we can use this number to determine accumulation per hour.
756,000 mg/min * 60 min/hr =
45,360,000 mg/hr

8 0

3 years ago

What are the features of nanotechnology?

grigory [225]

Answer:

Characteristics of Nanotechnology

Explanation:

Nanotechnology deals with putting things together atom by atom and with structures so small they are invisible to the naked eye. It provides the ability to create materials, devices and systems with fundamentally new functions and properties

7 0

4 years ago

Buckets and a Pulley Two buckets of sand hang from opposite ends of a rope that passes over an ideal pulley. One bucket is full

marin [14]

Answer:

A: T = 120 N

B: T = 88.42 N

C: T = 70 N

Explanation:

Part A:

Since, the lighter bucket is supported by my had. So, the only unbalanced force in the system is the weight of heavier bucket. Hence, the tension in rope will be equal to the weight of heavier bucket.

T = 120 N

Part B:

This is the case where, two masses hang vertically on both sides of the pulley. To find the tension in such case we have the formula:

T = (2 m₁m₂g)/(m₁+m₂)

where,

m₁ = mass of heavier object = W₁/g = (120 N)/(9.8 m/s²) = 12.24 kg

m₁ = mass of lighter object = W₂/g = (70 N)/(9.8 m/s²) = 7.14 kg

g = 9.8 m/s²

Therefore,

T = [(2)(12.24 kg)(7.14 kg)(9.8 m/s²)]/(12.24kg + 7.14 kg)

T = 1713.6 N.kg/19.38 kg

T = 88.42 N

Part C:

Since, the heavier bucket is on ground. So, its weight is balanced by the normal reaction of the ground. The only unbalanced force in the system is the weight of lighter bucket. Hence, the tension in rope will be equal to the weight of lighter bucket.

T = 70 N

4 0

3 years ago