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Blababa [14]
3 years ago
13

Plsss help I’ll give u brainlest and 10 points number 13 pls

Mathematics
1 answer:
yuradex [85]3 years ago
8 0

Answer:

A

Step-by-step explanation:

I added 6.5 to the equation, found the mean, and it was 3.5.

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Answer please lot's of points.
Svetlanka [38]

Answer:

t≈8.0927

Step-by-step explanation:

h(t) = -16t^2 + 128t +12

We want to find when h(t) is zero ( or when it hits the ground)

0 =  -16t^2 + 128t +12

Completing the square

Subtract 12 from each side

-12  =  -16t^2 + 128t

Divide each side by -16

-12/-16  =  -16/-16t^2 + 128/-16t

3/4 = t^2 -8t

Take the coefficient of t and divide it by 8

-8/2 = -4

Then square it

(-4) ^2 = 16

Add 16 to each side

16+3/4 = t^2 -8t+16

64/4 + 3/4= (t-4)^2

67/4 = (t-4)^2

Take the square root of each side

±sqrt(67/4) =sqrt( (t-4)^2)

±1/2sqrt(67) = (t-4)

Add 4 to each side

4 ±1/2sqrt(67) = t

The approximate values for t are

t≈-0.092676

t≈8.0927

The first is before the rocket is launched so the only valid answer is the second one

3 0
3 years ago
Read 2 more answers
Please write the answer​
Travka [436]

\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)}  \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\  \\ \longrightarrow \sf \: 27 - 15 \\  \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}

6 0
3 years ago
What is a and b pls answer ASAP I need it !!! Plsss
nlexa [21]

Answer:

The value of a = 5.

the value of b = 6.

Step-by-step explanation:

Given the points on the line

  • (6, 10)
  • (a, 8)
  • (4, b)
  • (2, 2)

Given that all of the points are on the same line and the line represents a linear function.

Thus, the slope between any two points must be the same.

First, determine the slope between (6, 10) and (2, 2)

(x₁, y₁) = (6, 10)

(x₂, y₂) = (2, 2)

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]

               =  [2 - 10] / [2 - 6]

               = -8 / -4  

               = 2

Thus, the slope of the line = m = 2

Determine the value 'a'

(x₁, y₁) = (6, 10)

(x₂, y₂) = (a, 8)

Using the slope formula to determine the value of 'a'

Slope =  [y₂ - y₁] /  [x₂ - x₁]

As the slope between two points is 2.

now substitute slope = 2, (x₁, y₁) = (6, 10) and (x₂, y₂) = (a, 8) in the slope formula

Slope =  [y₂ - y₁] /  [x₂ - x₁]

2 = [8 - 10] / [a - 6]

2(a - 6) = 8 - 10

2a - 12 = -2

2a = -2 + 12

2a = 10

divide both sides by 2

a = 5

Therefore, the value of a = 5.

Determine the value 'b'

(x₁, y₁) = (2, 2)

(x₂, y₂) = (4, b)

Using the slope formula to determine the value of 'b'

Slope =  [y₂ - y₁] /  [x₂ - x₁]

As the slope between two points is 2.

now substitute slope = 2, (x₁, y₁) = (2, 2) and (x₂, y₂) = (4, b) in the slope formula

Slope =  [y₂ - y₁] /  [x₂ - x₁]

2 = [b - 2] / [4 - 2]

2(4 - 2) = b - 2

8 - 4 =b - 2

4 = b - 2

b = 6

Therefore, the value of b = 6

7 0
3 years ago
2 and 5. What is the LCM?
Masja [62]
Well, first of all, LCM means Lowest Common Multiple. So you have to write out the factors of each of the numbers. So that will be;
2= 2, 4, 6, 8, 10, 12, 14, 16, 18, 20
5=5, 10, 15, 20
  So now, you have to pick out the numbers that are common to both numbers. So;
10, 20
  10 and 20 are the only common numbers. So you have to look for the lowest common number. And that is 10. So the LCM is 10.. Hope i helped. Have a nice day. 
5 0
3 years ago
A sand dune stands 5 feet above sea level. The hill is eroding at a rate of 1 foot per 20 years. Let y represent the height of t
avanturin [10]
y = -1/2x + 5 should be your equation because it is 5 ft above sea level and its eroding, or going down, 1 ft per 20 years. So every year, the sand dune erodes 1/20 ft more.

Hope this helps!
4 0
3 years ago
Read 2 more answers
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