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3 years ago

I need help with all of these pls help me thx for ur time

Mathematics

2 answers:

Vikentia [17]3 years ago

8 0

Oh dam he answered wild

zavuch27 [327]3 years ago

5 0

Answers:

1: No, 10/12 Simplified is 5/6, and 15/30 simplified is 1/2

2: Yes, 1/5 / 3/5 Simplified is 1/3, and 1/4 / 3/4 simplified is 1/3

3: 60 words, You do 300 divided by 5, and you get 60 per minute

4: 240 words, You take the 60 per minute, and you multiply is by 4.

5: 24 doughnuts, 20x3 is 60 minutes. So, 12 doughnuts in one hour. Multiply is by 2, and you get 24 doughnuts per hour.

6: Walmart, To find out how much it costs, you so 1.25 / 5, and 0.80 / 2. So, Walmart is 0.25 per pack, and Ingles is 0.40 per pack. So, you can automatically tell that Walmart is cheaper, meaning the better buy.

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robin has some bananas. 6 bananas are ripe. three fifths of he bananas are ripe. how many bananas does robin have in all

REY [17]

6 = 3/5 x
30 = 3x
x=10 bananas

7 0

3 years ago

Read 2 more answers

As a store manger you would like to find out the average time it takes to unload the truck which delivers the merchandise for yo

Georgia [21]

Answer:

The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes

Step-by-step explanation:

We have the standard deviation for the sample, but not for the population, so we use the students t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 35 - 1 = 35

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.975([tex]t_{975}$ ). So we have T = 2.0322

The margin of error is:

M = T*s = 2.0322*30 = 60.97

The upper end of the interval is the sample mean added to M. So it is 204 + 60.97 = 264.97

The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes

4 0

3 years ago

Read 2 more answers

A lampshade has a height of 12cm and upper and lower diameters of 10cm and 20cm A)what area of material is required to cover tha

netineya [11]

Answer:

$(a)\ Area = 195\pi$

$(b)\ Volume = 700\pi$

Step-by-step explanation:

Given

$h = 12$

$d_1 = 10$ --- lower diameter

$d_2 = 20$ --- upper diameter

Solving (a): The curved surface area

This is calculated as:

$Area = \pi l(r_1 + r_2)$

Where

$r_1 = 0.5 * d_1 = 0.5 * 10 = 5$ --- lower radius

$r_2 = 0.5 * d_2 = 0.5 * 20 = 10$ --- upper radius

And

$l = \sqrt{h^2 + (r_1 - r_2)^2$ ---- l represents the slant height of the frustrum

$l = \sqrt{12^2 + (5 - 10)^2$

$l = \sqrt{12^2 + (-5)^2$

$l = \sqrt{144 + 25$

$l = \sqrt{169$

$l = 13$

So, we have:

$Area = \pi l(r_1 + r_2)$

$Area = \pi * 13(5 + 10)$

$Area = \pi * 13(15)$

$Area = 195\pi$

Solving (b): The volume

This is calculated as:

$Volume = \frac{1}{3}\pi * h * (r_1^2 + r_2^2 + (r_1 * r_2))$

This gives:

$Volume = \frac{1}{3}\pi * 12 * (5^2 + 10^2 + (5 * 10))$

$Volume = \frac{1}{3}\pi * 12 * (25 + 100 + (50))$

$Volume = \frac{1}{3}\pi * 12 * (175)$

$Volume = \pi *4 * 175$

$Volume = 700\pi$

6 0

3 years ago

What's <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B50%20-%201%7D%20" id="TexFormula1" title=" \sqrt{50 - 1} " alt=" \sqrt

nikklg [1K]

Inside the root is 50-1

50-1 = 49

You would remain with root 49 but, if you calculate the square root the answer would be 7 because...

7•7 = 49

^ So, the answer is 7

4 0

3 years ago

Read 2 more answers

Bryce is solving this problem.

zavuch27 [327]

Answer:

The answer is C

2.640 and 10,560

Step-by-step explanation:

264 * 410 = (264 * 400) + (264 * 10) = 105,600 + 2640 = 2.640 and 10,560

6 0

3 years ago