the puck recoils in each case.
larger mass stone gives puck greater recoil, smaller stone, smaller recoil
a) 10 m/s
b) 25 m
Explanation:
a)
The body is moving with a constant acceleration, therefore we can solve the problem by using the following suvat equation:
![v=u+at](https://tex.z-dn.net/?f=v%3Du%2Bat)
where
u is the initial velocity
v is the final velocity
a is the acceleration
t is the time
For the body in this problem:
u = 0 (the body starts from rest)
is the acceleration
t = 5 s is the time
So, the final velocity is
![v=0+(2)(5)=10 m/s](https://tex.z-dn.net/?f=v%3D0%2B%282%29%285%29%3D10%20m%2Fs)
b)
In this second part, we want to calculate the distance travelled by the body.
We can do it by using another suvat equation:
![v^2-u^2=2as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2as)
where
u is the initial velocity
v is the final velocity
a is the acceleration
s is the distance travelled
Here we have
u = 0 (the body starts from rest)
is the acceleration
v = 10 m/s is the final velocity
Solving for s,
![s=\frac{10^2-0^2}{2(2)}=25 m](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B10%5E2-0%5E2%7D%7B2%282%29%7D%3D25%20m)
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
![f= -75 \ cm = - 0.75 \ m](https://tex.z-dn.net/?f=f%3D%20%20-75%20%5C%20cm%20%3D%20%20-%200.75%20%5C%20m)
b
![P = -1.33 \ diopters](https://tex.z-dn.net/?f=P%20%20%3D%20%20-1.33%20%5C%20diopters)
Explanation:
From the question we are told that
The image distance is ![d_i = -75 cm](https://tex.z-dn.net/?f=d_i%20%3D%20%20-75%20cm)
The value of the image is negative because it is on the same side with the corrective glasses
The object distance is ![d_o = \infty](https://tex.z-dn.net/?f=d_o%20%3D%20%20%5Cinfty)
The reason object distance is because the object father than it being picture by the eye
General focal length is mathematically represented as
![\frac{1}{f} = \frac{1}{d_i} - \frac{1}{d_o}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7Bd_i%7D%20%20-%20%20%20%5Cfrac%7B1%7D%7Bd_o%7D)
substituting values
![\frac{1}{f} = \frac{1}{-75} - \frac{1}{\infty}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bf%7D%20%20%3D%20%20%5Cfrac%7B1%7D%7B-75%7D%20%20-%20%20%20%5Cfrac%7B1%7D%7B%5Cinfty%7D)
=> ![f= -75 \ cm = - 0.75 \ m](https://tex.z-dn.net/?f=f%3D%20%20-75%20%5C%20cm%20%3D%20%20-%200.75%20%5C%20m)
Generally the power of the corrective lens is mathematically represented as
![P = \frac{1}{f}](https://tex.z-dn.net/?f=P%20%20%3D%20%20%5Cfrac%7B1%7D%7Bf%7D)
substituting values
![P = \frac{1}{-0.75}](https://tex.z-dn.net/?f=P%20%20%3D%20%20%5Cfrac%7B1%7D%7B-0.75%7D)
![P = -1.33 \ diopters](https://tex.z-dn.net/?f=P%20%20%3D%20%20-1.33%20%5C%20diopters)
Festival dances can help improve your fitness because your moving and exercising your body without even knowing for hours therefore it helps with weight loss and your health in general.