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Roman55 [17]
3 years ago
8

How much time does it take the shock wave arrive

Physics
1 answer:
prisoha [69]3 years ago
7 0

Answer: It could take 15 minutes to 36 hours.

Explanation: It depends on the intensity.

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If the voltage impressed across a circuit is held constant while the resistance doubles, what change occurs in the current?
bazaltina [42]

Answer:

The current halves

Explanation:

The relationship between voltage, current and resistance in a circuit is given by Ohm's law:

V=RI

where

V is the voltage

R is the resistance

I is the current

We can rewrite the formula as

I=\frac{V}{R}

we see that I is directly proportional to V and inversely proportional to R.  In this problem, V is held constant while R is doubled:

R'=2R

so, the new current in the circuit will be

I'=\frac{V}{R'}=\frac{V}{2R}=\frac{1}{2}I

So, the current halves.

4 0
4 years ago
If the voltage in a circuit is 24 V and the current is 2 A, what is the total power in the circuit?
Drupady [299]
Maybe you can divide the volts its twelve if you do that but itll show you how much to double it by

5 0
4 years ago
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Researchers condition a flatworm to contract when exposed to light by repeatedly pairing the light with electric shock. the elec
Serga [27]
Negative Reinforcement
5 0
3 years ago
In the human eye, the receptors that are responsible for our ability to see color are called ___
dusya [7]
The answer is A. Cones, as rods are not sensitive to color. :) 
5 0
3 years ago
A force of 44 N will stretch a rubber band 88 cm ​(0.080.08 ​m). Assuming that​ Hooke's law​ applies, how far will aa 11​-N forc
Setler79 [48]

Answer:

<em>The rubber band will be stretched 0.02 m.</em>

<em>The work done in stretching is 0.11 J.</em>

Explanation:

Force 1 = 44 N

extension of rubber band = 0.080 m

Force 2 = 11 N

extension = ?

According to Hooke's Law, force applied is proportional to the extension provided elastic limit is not extended.

F = ke

where k = constant of elasticity

e = extension of the material

F = force applied.

For the first case,

44 = 0.080K

K = 44/0.080 = 550 N/m

For the second situation involving the same rubber band

Force = 11 N

e = 550 N/m

11 = 550e

extension e = 11/550 = <em>0.02 m</em>

<em>The work done to stretch the rubber band this far is equal to the potential energy stored within the rubber due to the stretch</em>. This is in line with energy conservation.

potential energy stored = \frac{1}{2}ke^{2}

==> \frac{1}{2}* 550* 0.02^{2} = <em>0.11 J</em>

3 0
3 years ago
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