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3 years ago

6

A sailboat picks up a gust of wind and accelerates to a speed of 6m/s in 16 seconds.If the initial velocity 1 m/s,what is the ac

celeration of the sailboat

1 answer:

noname [10]3 years ago

3 0

Answer:

0.3125m/s

Explanation:

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A miniature quadcopter is located at x = -2.25 m and y, - 5.70 matt - 0 and moves with an average velocity having components Vv,

kupik [55]

Recall that average velocity is equal to change in position over a given time interval,

$\vec v_{\rm ave} = \dfrac{\Delta \vec r}{\Delta t}$

so that the <em>x</em>-component of $\vec v_{\rm ave}$ is

$\dfrac{x_2 - (-2.25\,\mathrm m)}{1.60\,\mathrm s} = 2.70\dfrac{\rm m}{\rm s}$

and its <em>y</em>-component is

$\dfrac{y_2 - 5.70\,\mathrm m}{1.60\,\mathrm s} = -2.50\dfrac{\rm m}{\rm s}$

Solve for $x_2$ and $y_2$ , which are the <em>x</em>- and <em>y</em>-components of the copter's position vector after <em>t</em> = 1.60 s.

$x_2 = -2.25\,\mathrm m + \left(2.70\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{x_2 = 2.07\,\mathrm m}$

$y_2 = 5.70\,\mathrm m + \left(-2.50\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{y_2 = 1.70\,\mathrm m}$

Note that I'm reading the given details as

$x_1 = -2.25\,\mathrm m \\\\ y_1 = -5.70\,\mathrm m \\\\ v_x = 2.70\dfrac{\rm m}{\rm s}\\\\ v_y=-2.50\dfrac{\rm m}{\rm s}$

so if any of these are incorrect, you should make the appropriate adjustments to the work above.

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3 years ago

101.32 + 20.1234 - 212.1 determine total number of significant figures

Leviafan [203]

Answer:

The total number of significant figures is twelve.

Explanation:

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3 years ago

Joe is trying to soup up his dragster. He knows that the time needed for the car to go from 0 to 100 miles per hour varies inver

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3 years ago

The binding energy of a nucleus is the energy equivalent of the mass discrepancy.

Dima020 [189]

ANSWER IS NOT FALSE IT IS True

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2 years ago

Si usted trata de contrabandear lingotes de oro llenando su mochila, cuyas dimensiones son de 56 cm * 28 cm * 22 cm, ¿cuál sería

kati45 [8]

Answer:

Mass, m = 665.77 kg

Explanation:

The question says that "If you try to smuggle gold bars by filling your backpack, whose dimensions are 56 cm * 28 cm * 22 cm, what would be its mass? "

The dimension of gold bar is 56 cm×28 cm×22 cm

We know that the density of gold is 19.3 g/cm³

The mas per unit volume of a material is called its density. It can be given by :

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So, the mass of the gold bar is 665.77 kg.

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2 years ago