Infrared waves are an example of heat transfer by

In which grouping of the periodic table do the elements have simliar properties

STatiana [176]

I would have to say [c]

but it could also be [b]

3 0

4 years ago

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I need help!! Following measurements

Anna71 [15]

I am so sorry I do not know but I need to answer a question in order to ask one I hope u pass:))

5 0

3 years ago

Which relationship can be used to aid in the determination of the heat absorbed by bomb calorimeter?

NARA [144]

Answer:

ΔH = $q_{p}$

Explanation:

In a calorimeter, when there is a complete combustion within the calorimeter, the heat given off in the combustion is used to raise the thermal energy of the water and the calorimeter.

The heat transfer is represented by

$q_{com}$ = $q_{p}$

where

$q_{p}$ = the internal heat gained by the whole calorimeter mass system, which is the water, as well as the calorimeter itself.

$q_{com}$ = the heat of combustion

Also, we know that the total heat change of the any system is

ΔH = ΔQ + ΔW

where

ΔH = the total heat absorbed by the system

ΔQ = the internal heat absorbed by the system which in this case is $q_{p}$

ΔW = work done on the system due to a change in volume. Since the volume of the calorimeter system does not change, then ΔW = 0

substituting into the heat change equation

ΔH = $q_{p}$ + 0

==> ΔH = $q_{p}$

5 0

4 years ago

For an atom of chlorine-35, what number would you put as the SUPERSCRIPT in the atomic notation?

kobusy [5.1K]

<h2>Answer:</h2><h3>CI.Strictly speaking,the subscript is unnecessary ,since all atoms of cholorine have 17 protons.Hence the isotope symbols are usually written withouth the subscript.³⁵CI and ³⁷CI</h3>

<h2>EXPLANATION:</h2><h2>I HPE IT HELP THANK YOU!</h2>

6 0

3 years ago

What is the volume of a gas if 0.182 moles of the gas is at 1.99 atm and 83.4oC?

Pie

$\text{Given that,}\\\\\text{Pressure,}~ P = 1.99~ \text{atm}\\ \\\text{No. of moles,}~ n = 0.182~ \text{mol.}\\\\\text{Temperature,}~ T = 83.4^{\circ}~ C = 356.4~K\\\\ \text{Molar gas constant,}~ R = 0.082~ \text{L}~ \text{atm}~ \text{mol}^{-1}~ \text{K}^{-1}\\\\\text{Volume,}~ V =?\\\\\text{We know that,}~\\\\~~~~~~~PV =nRT\\\\\implies V = \dfrac{nRT}{P}\\\\\\~~~~~~~~~~=\dfrac{0.182 \times0.082 \times 356.4 }{1.99}\\\\\\~~~~~~~~~~\approx 2.68~ \text{L.}\\\\\\$

$\text{Hence the volume of the gas is 2.68 L.}$

6 0

2 years ago

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