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lys-0071 [83]
3 years ago
15

Hello i need help someone please!!find the inverse of this relation h(t) = -6t + 7

Mathematics
2 answers:
Basile [38]3 years ago
7 0

Answer:

h^{-1} (t) = \frac{7-t}{6}

Step-by-step explanation:

let y = h(t) and rearrange making t the subject

y = - 6t + 7 ( add 6t to both sides )

6t + y = 7 ( subtract y from both sides )

6t = 7 - y ( divide both sides by 6 )

t = \frac{7-y}{6}

Change y back into terms of x with t = h^{-1} (t)

h^{-1} (t) = \frac{7-t}{6}

gregori [183]3 years ago
6 0

Answer:

73

Step-by-step explanation:

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