Question

Hello i need help someone please!!find the inverse of this relation h(t) = -6t + 7

Answer 1

Answer:

$h^{-1}$ (t) = $\frac{7-t}{6}$

Step-by-step explanation:

let y = h(t) and rearrange making t the subject

y = - 6t + 7 ( add 6t to both sides )

6t + y = 7 ( subtract y from both sides )

6t = 7 - y ( divide both sides by 6 )

t = $\frac{7-y}{6}$

Change y back into terms of x with t = $h^{-1}$ (t)

$h^{-1}$ (t) = $\frac{7-t}{6}$

Answer 2

Answer:

73

Step-by-step explanation: