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Anna007 [38]
3 years ago
13

I notice the wheels on my bicycle spin in a circular motion as I am pedaling. I know that the

Physics
1 answer:
kherson [118]3 years ago
6 0

Answer:

Acceleration, a = 750m/s²

Explanation:

Given the following data;

Radius, r = 0.31m

Velocity, v = 15m/s

To find the centripetal acceleration;

Acceleration, a = \frac {v^{2}}{r}

Substituting into the equation, we have;

Acceleration, a = \frac {15^{2}}{0.31}

Acceleration, a = \frac {225}{0.31}

Acceleration, a = 750m/s²

Therefore, the centripetal acceleration of the bike wheel is 750m/s².

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The blade of a windshield wiper moves through an angle of 180.0 degrees in 0.500 s. The tip of the blade moves on the arc of a c
sweet-ann [11.9K]

Answer:

Centripetal acceleration will be equal to 10.66m/sec^2

Explanation:

We have given time taken to cover 180° is 0.5 sec

So time taken by 360° is equal to = 2×0.5 = 1 sec

Radius of the circle r = 0.520 m

So distance d=2\pi r=2\times3.14\times 0.520=3.2656m

So velocity v=\frac{distance}{time}=\frac{.2656}{1}=3.2656m/sec

We have to find the centripetal acceleration

Centripetal acceleration will be equal to a_c=\frac{v^2}{r}=\frac{3.2656^2}{1}=10.66m/sec^2

So centripetal acceleration will be equal to 10.66m/sec^2

7 0
4 years ago
What is gravitational potential energy?
Kay [80]

Answer:

D). energy resulting from the attraction between two masses.

Explanation:

4 0
3 years ago
12 g … _____________________kilograms
Julli [10]
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4 years ago
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Find the center of mass (in cm) of a one-meter long rod, made of 50 cm of copper (density 8.92 g/cm3) and 50 cm of iron (density
Gennadij [26K]

Answer

given,

copper rod length = 50 cm

density of the copper = 8.92 g/cm³

iron rod length = 50 cm

density of iron = 7.86 g/cm³

mass of iron = density × volume

               m_i = 7.86 × A × l/2

               m_c = 8.96 × A × l/2

taking  the intersection of copper and iron rod be starting point cooper side is taken as positive side and iron side length is taken to be  -ve side.

center of mass

 = \dfrac{m_i\times \dfrac{-l}{4}+m_c\times \dfrac{l}{4}}{m_i+m_c}

 = \dfrac{7.86\times A \times \dfrac{l}{2}\times \dfrac{-l}{4}+8.96\times A \times \dfrac{l}{2}\times \dfrac{l}{4}}{7.86\times A \times \dfrac{l}{2}+8.96\times A \times \dfrac{l}{2}}

 = \dfrac{7.86\times \dfrac{-l}{4}+8.92\times \dfrac{l}{4}}{7.86+8.92}

 = \dfrac{1.06\dfrac{l}{4}}{16.78}

 = 0.015793 m

 = 1.579 m (+ve)

center of mass shift to cooper because cooper is heavy.

4 0
3 years ago
12.
vazorg [7]

Answer: A

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