Which should be done in case of a laboratory accident?

Can two negatively charged balloons move apart without ever touching why or why not

Nutka1998 [239]

Yes, because electric charges have electric field surrounding them that allow them to exert forces on other objects without touching them.

8 0

3 years ago

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Which land feature is formed by two oceanic tectonic plates diverging? *

qaws [65]

Answer:

mid-ocean ridge

Explanation:

When two oceanic tectonic plates diverge, it means they pull away from each other. When this happens, new land is created where the two plates moved apart.

5 0

3 years ago

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Using the equation for decay, calculate the amount left of a radioactive sample amount N0 if the decay constant is 0.00125 secon

makkiz [27]

The amount left of a radioactive sample amount N0 if the decay constant is 0.00125 seconds and the time is 180 seconds is 0.7999 N.

The time it takes for half of the original population of radioactive atoms to decay is called the half-life. The relationship between the half-life T1/2 and the decay constant is given by T1/2 = 0.693/λ.

N=N0e−λt
given λ = 0.00125 seconds
t = 180 seconds
Now putting values.
N=N0e−λt = 0.799
N= 0.7999.

Read more about the radioactive :

brainly.com/question/2320811

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5 0

2 years ago

A piston above liquid in a closed container has an area of 1m2. The piston carries a load of 350 kg. What will be the external p

grandymaker [24]

<span>Pressure = force / area</span>

I assume that 350kg is the mass
Therefore,

350 x 9.8 (gravity) = 3430N

3430 / 1 = 3430Pa

3.43 KPa

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3 years ago

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A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 6 ft from the path and is kept fo

BARSIC [14]

We are given that,

$\frac{dx}{dt} = 4ft/s$

We need to find $\frac{d\theta}{dt}$ when $x=8ft$

The equation that relates x and $\theta$ can be written as,

$\frac{x}{6} tan\theta$

$x = 6tan\theta$

Differentiating each side with respect to t, we get,

$\frac{dx}{dt} = \frac{dx}{d\theta} \cdot \frac{d\theta}{dt}$

$\frac{dx}{dt} = (6sec^2\theta)\cdot \frac{d\theta}{dt}$

$\frac{d\theta}{dt} = \frac{1}{6sec^2\theta} \cdot \frac{dx}{dt}$

Replacing the value of the velocity

$\frac{d\theta}{dt} = \frac{1}{6} cos^2\theta (4)^2$

$\frac{d\theta}{dt} = \frac{8}{3} cos^2\theta$

The value of $cos \theta$ could be found if we know the length of the beam. With this value the equation can be approximated to the relationship between the sides of the triangle that is being formed in order to obtain the numerical value. If this relation is known for the value of x = 6ft, the mathematical relation is obtained. I will add a numerical example (although the answer would end in the previous point) If the length of the beam was 10, then we would have to

$cos\theta = \frac{6}{10}$

$\frac{d\theta}{dt} = \frac{8}{3} (\frac{6}{10})^2$

$\frac{d\theta}{dt} = \frac{24}{25}$

Search light is rotating at a rate of 0.96rad/s

4 0

3 years ago