1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mademuasel [1]
3 years ago
14

In a Young's double-slit experiment, a set of parallel slits with a separation of 0.102 mm is illuminated by light having a wave

length of 575 nm and the interference pattern observed on a screen 3.50 m from the slits.(a) What is the difference in path lengths from the two slits to the location of a second order bright fringe on the screen?(b) What is the difference in path lengths from the two slits to the location of the second dark fringe on the screen, away from the center of the pattern?
Physics
1 answer:
guajiro [1.7K]3 years ago
6 0

Answer:

Rounded to three significant figures:

(a) 2 \times 575\; \rm nm = 1150\; \rm nm = 1.15\times 10^{-6}\; \rm m.

(b) \displaystyle \left(1 + \frac{1}{2}\right) \times (575\;\rm nm) \approx 863\; \rm nm = 8.63\times 10^{-7}\; \rm m.

Explanation:

Consider a double-slit experiment where a wide beam of monochromatic light arrives at a filter with a double slit. On the other side of the filter, the two slits will appear like two point light sources that are in phase with each other. For each point on the screen, "path" refers to the length of the segment joining that point and each of the two slits. "Path difference" will thus refer to the difference between these two lengths.  

Let k denote a natural number (k \in \left\lbrace0,\, 1,\, 2,\, \dots\right\rbrace.) In a double-split experiment of a monochromatic light:

  • A maximum (a bright fringe) is produced when light from the two slits arrive while they were in-phase. That happens when the path difference is an integer multiple of wavelength. That is: \text{Path difference} = k\, \lambda.
  • Similarly, a minimum (a dark fringe) is produced when light from the two slits arrive out of phase by exactly one-half of the cycle. For example, The first wave would be at peak while the second would be at a crest when they arrive at the screen. That happens when the path difference is an integer multiple of wavelength plus one-half of the wavelength: \displaystyle \text{Path difference} = \left(k + \frac{1}{2}\right)\cdot \lambda.
<h3 /><h3>Maxima</h3>

The path difference is at a minimum (zero) at the center of the screen between the two slits. That's the position of the first maximum- the central maximum, a bright fringe where k = 0 in \text{Path difference} = 0.

The path difference increases while moving on the screen away from the center. The first order maximum is at k = 1 where \text{Path difference} = \lambda.

Similarly, the second order maximum is at k = 2 where \text{Path difference} = 2\, \lambda. For the light in this question, at the second order maximum: \text{Path difference} = 2\, \lambda = 2 \times 575\; \rm nm = 1.15\times 10^{-6}\; \rm m.

  • Central maximum: k = 0, such that \text{Path difference} = 0.
  • First maximum: k = 1, such that \text{Path difference} = \lambda.
  • Second maximum: k = 2, such that \text{Path difference} = 2\, \lambda.

<h3>Minima</h3>

The dark fringe closest to the center of the screen is the first minimum. \displaystyle \text{Path difference} = \left(0 + \frac{1}{2}\right)\cdot \lambda = \frac{1}{2}\, \lambda at that point.

Add one wavelength to that path difference gives another dark fringe- the second minimum. \displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda at that point.

  • First minimum: k =0, such that \displaystyle \text{Path difference} = \frac{1}{2}\, \lambda.
  • Second minimum: k =1, such that \displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda.

For the light in this question, at the second order minimum: \displaystyle \text{Path difference} = \left(1 + \frac{1}{2}\right)\cdot \lambda =  \left(1 + \frac{1}{2}\right)\times (575\; \rm nm) \approx 8.63\times 10^{-7}\; \rm m.

You might be interested in
How does earth's magnetic field behave through long periods of geologic time?
I am Lyosha [343]
It Irregularly Reverses. I got the answer right on the test.
7 0
3 years ago
Read 2 more answers
What is the formula for volume using density and mass
lawyer [7]

The definition of density is

                                                       Density                  = (mass) / (volume)

Multiply each side by 'volume' :    (density) x (volume) = (mass)

Divide each side by 'density' :                         Volume = (mass) / (density)
 

5 0
3 years ago
Read 2 more answers
Two charged point particle are located at two vertices of an equilateral triangle and the electric field is zero at the third ve
Debora [2.8K]

Answer:

Option E

Explanation:

In the presence of two point charges at the two vertices of an equilateral triangle, the resultant electric field at the third vertex due to these charges can not be zero whether the charges are identical or not.

The reason being that only of the x or y component of the field can be cancelled out in either case still the total field can't be reduced to zero.

This can only be achieved if another charge is present.

4 0
3 years ago
The position vector of a particle of mass 1.65 kg as a function of time is given by = (6.00 î + 4.15 t ĵ), where is in meters an
SashulF [63]

Answer:

 L = 41.09 Kg m2 / s      The angular momentum does not depend on the time

Explanation:

The definition of angular momentum is

        L = r x p

Where blacks indicate vectors

Let's apply this definition our case. Linear momentum

      p = m v

Let's replace

      L = m r x v

The given function is

      x = 6.00 i ^ + 4.15 t j ^

We look for speed

     v = dx / dt

     v = 0 + 4.15 j ^

To evaluate the angular momentum one of the best ways is to use determinants

     L = m \left[\begin{array}{ccc}i&j&k\\6&4.15t&0\\0&4.15&0\end{array}\right]

      L = m 6 4.15 k ^

The other products give zero

Let's calculate

      L = 1.65 6 4.15 k ^

      L = 41.09 Kg m2 / s

The angular momentum does not depend on the time

7 0
3 years ago
Newton’s second law of motion addresses the relationship between what two variables that influence the force on a body?
IgorC [24]

Newton’s Second Law concerns the generation of force based on an object’s mass and acceleration, as described by the equation F=ma.

Hope this helps!

8 0
3 years ago
Read 2 more answers
Other questions:
  • When you set something down on the ground what kind of work is your arm doing
    10·2 answers
  • Asbestos, HPV, chemicals found in tobacco smoke, and exposure to radioactivity and UV radiation are causes of
    6·1 answer
  • What are some of the physical properties of stars?
    13·1 answer
  • 10. Juan wants to see how air expands when it is heated. He is able to use any of the following supplies - a balloon, a heat lam
    6·2 answers
  • Surviving a ship wreck, what is the minimum mass of wood (density 60% that of sea water) necessary to support a 70kg woman stand
    6·1 answer
  • Foraging bees often move in straight lines away from and toward their hives. Suppose a bee starts at its hive and flies 680 m du
    10·1 answer
  • A 65kg has the weight force of
    9·1 answer
  • PLEASE HELP!!
    9·1 answer
  • What is the best definition of
    7·1 answer
  • The 3kg object in figure is released from rest at height of on a curved frictionless ramp. at the foot of the ramp is a spring o
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!