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MrRa [10]
3 years ago
5

A 24.8 cm tall object is placed in front of a lens, which creates a -3.09 cm tall image. If the object is 37.5 cm from the lens,

what is the image distance? pls help
Physics
1 answer:
Iteru [2.4K]3 years ago
5 0

Answer:

v = 4.67 m

Explanation:

It is given that,

Height of the object is 24.8 cm

Height of the formed image is -3.09 cm

Object distance is 37.5 cm, it is negative always

We need to find the image distance. Let v is the image distance. Magnification of an object is given by the formula as follows :

\dfrac{h'}{h}=\dfrac{v}{u}\\\\v=\dfrac{uh'}{h}\\\\v=\dfrac{-37.5\times (-3.09)}{24.8}\\\\v=4.67\ m

So, the image is formed at a distance of 4.67 m.

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