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MrRa [10]
3 years ago
5

A 24.8 cm tall object is placed in front of a lens, which creates a -3.09 cm tall image. If the object is 37.5 cm from the lens,

what is the image distance? pls help
Physics
1 answer:
Iteru [2.4K]3 years ago
5 0

Answer:

v = 4.67 m

Explanation:

It is given that,

Height of the object is 24.8 cm

Height of the formed image is -3.09 cm

Object distance is 37.5 cm, it is negative always

We need to find the image distance. Let v is the image distance. Magnification of an object is given by the formula as follows :

\dfrac{h'}{h}=\dfrac{v}{u}\\\\v=\dfrac{uh'}{h}\\\\v=\dfrac{-37.5\times (-3.09)}{24.8}\\\\v=4.67\ m

So, the image is formed at a distance of 4.67 m.

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What is the difference between acceleration and linear acceleration?
Akimi4 [234]

Explanation:

Linear acceleration is a type of acceleration of a body along a straight path or line.

Acceleration is defined as the rate of change of velocity with time.

  Acceleration = \frac{Change in velocity}{time}

There are different types of acceleration .

  • linear acceleration is used to describe the rate of change of velocity of a body along a straight path with time.
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6 0
3 years ago
How do we use soil to generate electricity?
Galina-37 [17]
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A body-centered cubic lattice has a lattice constant of 4.83 Ă. A plane cutting the lattice has intercepts of 9.66 Å, 19.32 Å, a
anastassius [24]

Answer:

Miller Indices are [2, 4, 3]

Solution:

As per the question:

Lattice Constant, C = 4.83 \AA

Intercepts along the three axes:

\bar{x} = 9.66 \AA

\bar{x} = 19.32 \AA

\bar{x} = 14.49 \AA

Now,

Miller Indices gives the vector representation of the atomic plane orientation in the lattice and are found by taking the reciprocal of the intercepts.

Now, for the Miller Indices along the three axes:

a = \frac{1}{9.66}

b = \frac{1}{19.32}

c = \frac{1}{14.49}

To find the Miller indices, we divide a, b and c by reciprocal of lattice constant 'C' respectively:

a' = \frac{\frac{1}{9.66}}{\frac{1}{4.83}} = \frac{1}{2}

b' = \frac{\frac{1}{19.32}}{\frac{1}{4.83}} = \frac{1}{4}

c' = \frac{\frac{1}{14.49}}{\frac{1}{4.83}} = \frac{1}{3}

7 0
3 years ago
Set up a parallel circuit with three resistors. Set up the battery to be 9 V, one resistor at 10 Ohms, the other at 21 Ohms, and
valina [46]

In a parallel circuit, the equivalent resistance is the reciprocal of (the sum of the individual reciprocals).

1/R = 1/10 + 1/21 + 1/13

1/R = 0.225 mhos

R = 4.45 ohms

I = V / R

The total current out of the battery is

I = (9v)/(4.45ohms)

I = 2.02 Amperes

As the total current leaves the battery, it splits into 3 paths, and each resistor gets part of it. The 10ohm resistor gets the most current; the 21ohm resistor gets the least current. After flowing through the resistors, the 3 currents join and add up to 2.02 Amperes again, and the same current returns to the battery.

Each resistor has the same 9v of EMF across it.

4 0
3 years ago
A mass m at the end of a spring vibrates with a frequency
Wittaler [7]

Answer:

m = 0.59 kg.

Explanation:

First, we need to find the relation between the frequency and mass on a spring.

The Hooke's law states that

F = -kx

And Newton's Second Law also states that

F = ma = m\frac{d^2x}{dt^2}

Combining two equations yields

a = -\frac{k}{m}x

The term that determines the proportionality between acceleration and position is defined as angular frequency, ω.

\omega = \sqrt{\frac{k}{m}}

And given that ω = 2πf

the relation between frequency and mass becomes

f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}.

Let's apply this to the variables in the question.

0.88 = \frac{1}{2\pi}\sqrt{\frac{k}{m}}\\0.60 = \frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}\\\frac{0.88}{0.60} = \frac{\frac{1}{2\pi}\sqrt{\frac{k}{m}}}{\frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}}\\1.4667 = \frac{\sqrt{m+0.68}}{\sqrt{m}}\\2.15m = m + 0.68\\1.15m = 0.68\\m = 0.59~kg

6 0
3 years ago
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