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irina [24]
3 years ago
13

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Physics
2 answers:
LiRa [457]3 years ago
8 0

Answer:

ah its invalid now

Explanation:

swat323 years ago
4 0

Answer:

if Josh ate 1/4 of a pizza what's the fraction of the pizza is left

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12.0-kg block is pushed across a rough horizontal surface by a force that is angled 30.0◦below thehorizontal. The magnitude of t
drek231 [11]

Answer: Fr = 26.53 N

Explanation: The constant force exerted on the block by the surface is the frictional force.

This frictional force is as a result of interaction between the body and the surface.

According to newton's second law of motion,

F - Fr = ma

F=applied force

Fr = magnitude of frictional force

m = mass of object = 12kg

a = acceleration of object = 3.2m/s²

The applied force (F= 75 N) is inclined at an angle of 30° to the horizontal thus making it have 2 components of forces given below

Fx = 75 * cos 30 = 64.95 N (horizontal component)

Fy = 75 * sin 30 = 37.5 N ( vertical motion)

The body moves across the surface, hence the horizontal component of force is responsible for motion.

F = 64.95 N

By substituting the parameters, we have that

64.96 - Fr = 12 * 3.2

64.96 - Fr = 38.4

Fr = 64.96 - 38.4

Fr = 26.53 N

7 0
3 years ago
Read 2 more answers
Two masses are attracted by a gravitational force of 7 N.
damaskus [11]

Answer:

The answer to your question is: F  = 0.4375 N. The force will be 16 times lower than with the first conditions.

Explanation:

Data

F = 7 N

F = ?  if the masses is quartered

Formula

F = \frac{Km1m2}{r2}

Process

Normal conditions F = Km₁m₂/r²  = 7              

When masses quartered        F = K(m₁/4)(m₂/4)/r²  = ?

                                                F = K(m₁m₂/16)/r²

                                                F = K(m₁m₂/16r²      = 7/16  = 0.4375 N

3 0
3 years ago
What is a key difference between cell signaling by a cell-surface receptor and cell signaling by an intracellular receptor?
Art [367]

CORRECT ANSWER:

a- Cell-surface receptors bind polar signaling molecules; intracellular receptors bind nonpolar signaling molecules.

STEP-BY-STEP EXPLANATION:

The complete question from book is

According to Figure 9.6, what is a key difference between cell signaling by a cell-surface receptor and cell signaling by an intracellular receptor?

a- Cell-surface receptors bind polar signaling molecules; intracellular receptors bind nonpolar signaling molecules.

b- Signaling molecules that bind to cell-surface receptors lead to cellular responses restricted to the cytoplasm; signaling molecules that bind to intracellular receptors lead to cellular responses restricted to the nucleus.

c- Cell-surface receptors bind to specific signaling molecules; intracellular receptors bind any signaling molecule.

d- Cell-surface receptors typically bind to signaling molecules that are smaller than those bound by intracellular receptors.

e- None of the other answer options is correct.

3 0
4 years ago
W
ludmilkaskok [199]

Answer: W represents an element Y represents a mixture

Explanation: I just took a quiz on this and got it right. Good Luck

4 0
3 years ago
Determine a submarines acceleration if it's initial velocity is 9.0 m/s and it travels 1.54 km in 2 min
julia-pushkina [17]
acceleration=\frac{\Delta v}{\Delta t}\\\\ \Delta t=2min=120s\\\\s=1,54km=1540m\\\\
acceleration=\frac{v_{f}-v_{i}}{\Delta t}\\\\
\Delta v=\frac{s}{t}\\
v_{f}-v_{i}=\frac{s}{t}\\
v_{f}=\frac{1540}{120}+9=21,83\frac{m}{s}\\\\
accleration=\frac{21,83-9}{120}=\frac{12,83}{120}=\boxed{0,107\frac{m}{s}}
6 0
3 years ago
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