Answer:
1.Solids have definate shape
2.Solids have definate volume.
3.Solids have definate made
4.Solids do not flow
Answer:
Molality = 8.57 m
Explanation:
Given data:
Molarity of solution = 5.73 M
density = 0.9327 g/mL
Molality of solution = ?
Solution:
Molality = moles of solute / kg of solvent.
Kg of solvent:
Mass of 1 L solution = density× volume
Mass of 1 L solution = 0.9327 g/mL × 1000 mL
Mass of 1 L solution = 932.7 g
Mass of solute:
Mass of 1 L = number of moles × molar mass
Mass = 5.73 mol × 46.068 g/mol
Mass = 263.97 g
Mass of solvent:
Mass of solvent = mass of solution - mass of solute
Mass of solvent = 932.7 g - 263.97 g
Mass of solvent = 668.73 g
In Kg = 668.73 /1000 = 0.6687 Kg
Molality:
Molality = number of moles of solute / mass of solvent in Kg
Molality = 5.73 mol / 0.6687 Kg
Molality = 8.57 m
Answer:
Explanation:
You must convert the 6.00 grams of H₂ into number of moles, and then use the stoichiometry of the reaction to find the number of moles of NH₃, which can be converted into volume using the ideal gas equation.
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<u>1. Number of moles of H</u><u>₂</u>
- number of moles = mass in grams / molar mass
- molar mass of H₂ = 2.016g/mol
- number of moles = 6.00grams / 2.016g/mol = 2.97619mol
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<u>2. Number of moles of NH</u><u>₃</u>
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i) Chemical equation:
ii) Mole ratio:
iii) Proportion:
- x mol NH₃ / 2.97619mol H₂ = 3 mol NH₃ / 2 mol H₂
<u>3. Volume of NH₃</u>
- V = 4.4642857mol × 0.08206 atm·liter/(K·mol) × 506K / 2.05atm
Answer:
2.7×10⁻³ mole
Explanation:
Applying
Q = it.............. Equation 1
Where Q = amount of charge, i = current, t = time
From the question,
Given: i = 0.860 A, t = 5 minutes = (5×60) seconds = 300 seconds
Subsitute these values into equation 1
Q = (0.860×300)
Q = 258 C
If one mole of electron has a charge of 96500 C
Then, x mole of electron will have a charge of 258 C
1 mole ⇒ 96500 C
X moles ⇒ 258 C
Solve for X
X = (258×1)/96500
X = 2.7×10⁻³ mole
B. Infrared light I'm pretty sure correct me if I am wrong hope this helped
