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2 years ago

Find the value of k so that the line through the given points has the given slope.

Mathematics

1 answer:

Kay [80]2 years ago

7 0

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (1, k) and (-1, -4) and the slope m = 3/2. Substitute:

$\dfrac{-4-k}{-1-1}=\dfrac{3}{2}\\\\\dfrac{-4-k}{-2}=\dfrac{3}{2}\qquad\text{multiply both sides by (-2)}\\\\-4-k=-3\qquad\text{add 4 to both sides}\\\\-k=1\qquad\text{change the signs}\\\\\boxed{k=-1}$

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Help please this is urgent

yulyashka [42]

Answer:

64 degrees.

Step-by-step explanation:

This is because the arrow that is not horizontal is pointing to that number.

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2 years ago

What is the answer? I am so lost- thanks for any help given.

aev [14]

Answer:

i think that the answer is 13 meters

Step-by-step explanation:

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2 years ago

Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm

Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 6, \sigma = 0.2$

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6-6}{0.2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X 5.8.

X = 6.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 5.8

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5-6}{0.2}$

$Z = -5$

$Z = -5$ has a pvalue of 0.

1 - 0 = 1

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2 years ago

Simplify <br> 1+sinx/cosx+cosx/1+sinx

Dmitry [639]

$\frac{1 + sin(x)}{cos(x)} + \frac{cos(x)}{1 + sin(x)}$
$\frac{[1 + sin(x)][1 +sin(x)]}{cos(x)[1 + sin(x)]} + \frac{cos(x)[cos(x)]}{cos(x)[1 + sin(x)]}$
$\frac{1 + 2sin(x) + sin^{2}(x)}{cos(x)[1 + sin(x)]} + \frac{cos^{2}(x)}{cos(x)[1 + sin(x)]}$
$\frac{1 + 2sin(x) + sin^{2}(x) + cos^{2}(x)}{cos(x)[1 + sin(x)]}$
$\frac{1 + 2sin(x) + 1}{cos(x)[1 + sin(x)]}$
$\frac{1 + 1 + 2sin(x)}{cos(x)[1 + sin(x)]}$
$\frac{2 + 2sin(x)}{cos(x)[1 + sin(x)]}$
$\frac{2[1 + sin(x)]}{cos(x)[1 + sin(x)]}$
$\frac{2}{cos(x)}$
$2sec(x)$

6 0

2 years ago

Each shape is 1 whole. What fraction greater than 1 names the parts that are shaded?

jeka94

Any number over its self. for example 1,999/1,999

5 0

3 years ago