A generic point on the graph of the curve has coordinates
The derivative gives us the slope of the tangent line at a given point:
Let k be a generic x-coordinate. The tangent line to the curve at this point will pass through 
and have slope 
So, we can write its equation using the point-slope formula: a line with slope m passing through 
has equation
In this case, 
and 
, so the equation becomes
We can rewrite the equation as follows:
We know that this function must give 0 when evaluated at x=0:
This equation has no real solution, so the problem looks impossible.
Part A:
Yes, the data represent a function because there is at least one x-value for every y-value.
Part B:
When x=6 in the input-output table, y=14. When x=6 in the relation f(x)=7x-15, f(x)=7(6)-15=27. <span>The equation has a greater value when x=6.
Part C:</span>
Set f(x) equal to 6 in the equation:
6=7x-15
Solve for x:
7x=21
x=3
<span>x=3 when f(x)=6</span>
Answer:
6th week.
Step-by-step explanation:
Each week he is selling 1/2 of the week before so
In the 3rd week he sells 400
- in the 4th week it will be 200
- in 5th week 100
- in 6th seek 50.
Answer:
x=136°
Step-by-step explanation:
x=180°-(180-(46+90))
x=180-44
x=136
Answer:
AA only
Step-by-step explanation:
A= Angle
S= Side
Both triangles only have 2 angles so it's AA (angle angle)
