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Julli [10]
3 years ago
12

2a^3+a^2–17–3a^2+a^3–a –80

Mathematics
1 answer:
adelina 88 [10]3 years ago
3 0

Answer:

=3a^3−2a^2−a−97

Step-by-step explanation:

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\large\bold{{Question :}}

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm find the radius of the circle.

\large\bold\red{\underline{Solution :-}}

Here, O is the center of the circle.

<u>⟼</u><u> </u><u>Given</u><u> </u><u>:</u>

  • OQ = 25 cm
  • PQ = 24 cm

<u>⟼</u><u> </u><u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u> </u> We have to find the radius OP.

Since QP is tangent, OP perpendicular to QP.

(Since, Tangent is Perpendicular to Radius ⠀⠀⠀⠀⠀⠀⠀at the point of contact)

So, ∠OPQ=90°

<u>⟼</u><u> </u><u>By</u><u> </u><u>Applying</u><u> </u><u>Pythagoras</u><u> </u><u>Theorem</u><u> </u><u>:</u>

OP² + RQ² = OQ²

OP² + (24)² = (25)²

OP² = 625 - 576

OP² = 49

OP = √49

<u>OP</u><u> </u><u>=</u><u> </u><u>7</u><u> </u><u>cm</u>

<u>Hence</u><u>,</u><u> </u><u>The</u><u> </u><u>Radius</u><u> </u><u>is</u><u> </u><u>7</u><u> </u><u>cm</u>

⠀⠀

⠀

<h3>-MissAbhi</h3>

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