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miss Akunina [59]
3 years ago
13

Whoever gives answer gets brainliest asap

Mathematics
1 answer:
arlik [135]3 years ago
8 0

Answer:

m=y2-y1/x2-x1 ⇒ m=-48+64/-15+21

m=16/6=8/3

y-y1/x-x1= m⇒ 8/3=y+64/x+21

8x+168=3y+192

    3y=8x-24

x-intercept

3(0)=8x-24

x=24/8 →x=3

<u>x-intercept: (3,0)</u>

<u>OAmalOHopeO</u>

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She will need 9 computers. She has 8 groups of 3 and 1 group of 2. Therefore, she will need 9.
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Solve the following inequality for g. Write your answer in simplest form.<br> -5-3(5g-4)≥2g+6-10
denpristay [2]

Answer:

g\leq \frac{11}{17}

Step-by-step explanation:

-5-3(5g-4)\geq 2g+6-10\\-5+(-15g+12)\geq 2g-4\\-5+(-15g)+12\geq 2g-4\\7-15g\geq 2g-4\\7\geq 17g-4\\3\geq 17g\\\frac{11}{17} \geq g\\g\leq \frac{11}{17}

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3 years ago
Using the transformation T: (x, y) (x + 2, y + 1), find the distance named.
kumpel [21]
A(0,0) A'(2,1)
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answer
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4 0
3 years ago
Read 2 more answers
For the point P (-17,25) and Q(-10,30), fins the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.
Nonamiya [84]

Answer:

Distance = 8.6

M = (-13.5,27.5)

Step-by-step explanation:

Distance = \sqrt{(x_{2 }- x_{1 })^2 + (y_{2 }- y_{1 })^2

= \sqrt{(-10_ }- (-17)_{ })^2 + (30_{ }- 25_{ })^2

= \sqrt{(-10_{ }+ 17_{ })^2 + 5^2_

= \sqrt{7^2+5^2}

= \sqrt{49+25}

= \sqrt{74}

= 8.6

Midpoint = (\frac{x_{2}+x_{1}}{2};\frac{y_{2}+y_{1}}{2})

= (-10+(-17)) ÷ 2 ; (30+25) ÷ 2

= -27 ÷2 ; 55 ÷ 2

= -13.5, 27.5

3 0
3 years ago
−2∣3−5x∣+5=<br> \,\,-13<br> −13
yaroslaw [1]

Answer: 59

Step-by-step explanation:

Mi said so

5 0
3 years ago
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