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3 years ago

Do i have to check all 3 sums for triangle inequality theorem

Mathematics

1 answer:

WARRIOR [948]3 years ago

6 0

It’s better if you do but now you don’t have to.

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Triangle PQR is transformed to triangle P′Q′R′. Triangle PQR has vertices P(4, −8), Q(0, 12), and R(−4, 0). Triangle P′Q′R′ has

Tom [10]

Part A:

The scale factor is 1/4, because you obtain the coordinates of points P', Q', R' by dividing the coordinates of P, Q and R respectively by 4.

Part B:

Reflecting about the y axis causes a sign swap in the x coordinate. So, the new point will be

$P''(-1, -2),\quad Q''(0, 3),\quad R''(1, 0)$

Part C:

The triangles are similar, but not congruent. When you transform PQR into P'Q'R', you get a scaled version of the original triangle. This means that the angles and the proportion between sizes will be the same, but the length are scaled by 1/4, and the area is consequentially scaled by 1/16.

Triangles P'Q'R' and P''Q''R'' are congruent, so they are both similar but not congruent to the original triangle.

6 0

3 years ago

Sum of natural numbers between 10 and 100 and divisible by 4

aleksklad [387]

Numbers 10-100 that are divisible by 4:

12
16
20
24
28
32
36
40
44
48
52
56
60
64
68
72
76
80
84
88
92
96
100

Total: 1288

7 0

3 years ago

3.6(5x4)divided 3+5.0=

mixas84 [53]

Answer:

29 Hope this helps

Step-by-step explanation:

"Given expression is :

First we will simplify both numerator and denominator separately using order of operations. So....

Thus the expression.... "

-Sicista

5 0

3 years ago

Help its urgent!! I can not figure it out!!

gladu [14]

What is the problem?

5 0

4 years ago

Find the center of the circle (x-2)^2+(y-8)^2=33

enyata [817]

Answer:

The center is (2,8)

Step-by-step explanation:

The equation of a circle is written as

(x-h)^2+ (y-k)^2 = r^2

where ( h,k) is the center and r is the radius

(x-2)^2+(y-8)^2=33

The center is (2,8) and the radius is sqrt(33)

6 0

4 years ago