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Bumek [7]
3 years ago
9

Bowl A contains three red and two white chips, and bowl B contains four red and three white chips. A chip is drawn at random fro

m bowl A and transferred to bowl B. Compute the probability of then drawing a red chip from bowl B.
Mathematics
1 answer:
____ [38]3 years ago
4 0

\Large \text {Answer:}

\large \boxed {\dfrac{23}{40}}

\Large \text {Step-by-step explanation:}

\text{P}_{B}(r) = \text{P}_{A}(r) \cdot \text{P}_{B}(r) + \text{P}_{A}(w) \cdot \text{P}_{B}(r)

\text{P}_{B}(r) = \left (\dfrac{3}{5} \right ) \negthickspace \left(\dfrac{5}{8}\right ) + \left (\dfrac{2}{5} \right ) \negthickspace \left (\dfrac{4}{8} \right )

\text{P}_{B}(r) = \dfrac{23}{40}

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13 minutesStep-by-step explanation:

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6=4y+2 what is the answer
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And, S2
dangina [55]

<u>Correct Question</u>

In the table shown, the sum of each row is shown to the right of the row and the sum of each column is shown below the column. What is the value of L?

\left|\begin{array}{c|c|c|c}-&-&-&-\\J&K&J&5\\K&K&L&13\\L&J&L&15\\-&-&-&-\\11&7&15\end{array}\right

Answer:

L=7

Step-by-step explanation:

From the first row: 2J+K=5

Therefore: K=5-2J

From the second column, 2K+J=7

Substitute K derived above into 2K+J=7

2K+J=7

2(5-2J)+J=7

10-4J+J=7

-3J=7-10

-3J=-3

J=1

Recall: K=5-2J

K=5-2(1)=3

K=3

From the third column, J+2L=15

1+2L=15

2L=15-1=14

L=7

Therefore, the value of L=7

CHECK:

\left|\begin{array}{c|c|c|c}-&-&-&-\\1&3&1&5\\3&3&7&13\\7&1&7&15\\-&-&-&-\\11&7&15\end{array}\right

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Answer:

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then divide by 4 which is 43 so the answer is w=43
8 0
3 years ago
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