All categories

3 years ago

1.

Mathematics

1 answer:

Vesnalui [34]3 years ago

8 0

1)4x-7=2x+9
Subtract 2x
2x-7= 9
Add 7
2x=16
X= 8

2(8)+9=25
(8,25)

X+y=10
-X-2y=-14
-y= -4
Y=4
X+4=10
X=6
(6,4)

You might be interested in

A cement block is in the shape of a rectangular prism that measures 4.5 feet by 7.25 feet by 6.5 feet. The entire block must be

irakobra [83]

I am pretty sure that if you are looking for perimeter there should only be two sets of numbers but if you are looking for area than the answer would be 212.0625

6 0

3 years ago

Read 2 more answers

It is -15° ourside and it increases 2° per hour what is the temperature adter 8 hours

neonofarm [45]

1°, because -15° + (2° × 8 hours) = 1°

7 0

3 years ago

Read 2 more answers

Vedant received two quotes for new carpet for his home. The quote from Company A is $0.15 less per square foot than the quote fr

dezoksy [38]

1200 x 0.15 = 180

so company a is cheaper by 180 dollars

3 0

3 years ago

Read 2 more answers

The area of the figure is BLANK square units.

nikitadnepr [17]

L*W*H

take them all and multipy

8 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

2 years ago

Read 2 more answers