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Elanso [62]
3 years ago
8

Can someone help with this one

Mathematics
1 answer:
Naya [18.7K]3 years ago
4 0

Answer:

2 bicycles

Step-by-step explanation:

  • let no. of bicycles be x
  • no.of tricycles = (6 -x)

as there were 5 bicycles and tricycles

now,

  • a bicycle has 2 wheels
  • a tricycle has 3 wheels

total no.of wheels = 16

2x + 3(6 - x) = 16

2x + 18 - 3x= 16

2 - x = 0

2 = x

therefore, there are 2 bicycles.

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What is the area of the paper used to wrap a can of soup if the can is 11 cm tall and has a diameter of 7.5 cm. Show all formula
Dimas [21]

Notice that a can is a cylinder, which is basically two circles and one rectangle. Now, the question wants area of this rectangle.

You know the width of the rectangle (or the paper), which is 11cm. How do you find the length then?

Notice that the length of the rectangle is also the circumference of the circles. From here, use C = πd where C is circumference and d is diameter. The d is given, which is 7.5 cm. Depending on the question, π can be 3.14, 22/7 or the actual pi.

multiply π and 7.5cm and you get the circumference. Multiply this to 11cm and you get area of the rectangle.

6 0
3 years ago
Sinx =căn 2/3<br> sinx=5/4<br> sinx =1<br> sin3x=can3/2<br> sin(x-60)=-1/2<br> sin3x=1/2
mel-nik [20]

Answer:

Correct option is

B

0

D

−1

sinx+sin2x+sin3x

=sin(2x−x)+sin2x+sin(2x+x)

=2sin2xcosx+sin2x [ by using sin(A+B)=sinAcosB+sinBcosA and sin(A−B)=sinAcosB−sinBcosA ]

=sin2x(2cosx+1)........(i)

cosx+cos2x+cos3x

=cos(2x−x)+cos2x+cos(2x+x)

=2cos2xcosx+cos2x [By using cos(a−b)=cosa⋅cosb+sina⋅sinb and cos(a+b)=cosa⋅cosb−sina⋅sinb]

=cos2x(2cosx+1).....(ii)

∴(sinx+sin2x+sin3x)

2

+(cosx+cos2x+cos3x)

2

=1

sin

2

2x(2cosx+1)

2

+cos

2

2x(2cosx+1)

2

=1.......[From(i)(ii)]

⇒(2cosx+1)

2

=1

⇒2cosx+1=±1

∴cosx=0or−1

6 0
3 years ago
Please help with the problem below! Thank you
Gwar [14]

Answer:

d \le -3

Step-by-step explanation:

The given inequality is;

\frac{d-3}{10} \ge \frac{2d+3}{5}+\frac{d+3}{3}

Clear the fraction by multiply through by 30;

3(d-3) \ge 6(2d+3)+10(d+3)

Expand;

3d-9\ge 12d+18+10d+30

Group like terms;

3d-12d-10d \ge 18+30+9

-19d \ge 57

Divide through by -19 and reverse the sign.

d \le -3

6 0
4 years ago
Read 2 more answers
Work out the value of angle x.<br> (24)<br> х<br> Isosceles
andreev551 [17]

answer:

x=78

since it's an isosceles triangle base angles are equal sum of all angles in traingle is 180 so

24+x+x=180

2x=156

x=78

hope.. this helped <3!!!

5 0
3 years ago
A jewelry maker has 24 jade beads and 30 teak beads. What is the greatest number of necklaces she can make? How many beads of ea
Zielflug [23.3K]
<span>In the given situation, a jewelry maker has the following:
=> 24 jade beads
=> 30 teak beads
Now, how many necklace can a jewelry maker make with this number of beads.
=> 24 + 30 = 54
=> (8 x 3) + (10 x  3) = 54
=> (8 + 10) x 3 = 54
=> 18 x 3 = 54
=> 54 = 54
Thus, the number of necklace is 3 with 8 jade and 10 teak beads in it.

</span>



4 0
4 years ago
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