The answer is 40 kg. m/s.
Formula for momentum:
p=mv
p=(10 kg.)(4 m/s)
So, therefore, the final answer is p=40 kg. m/s.
I hope this helped answer your question. Enjoy your day, and take care!
Answer:
It is easier to hear a musician in the classroom than outdoors
Explanation:
It is easier to hear a musician in the classroom due to the improved acoustics provided by the walls of the classroom whereby along with the direct sound of the musician, which is the lead source of the sounds, there is an increased number of indirect sound reaching the ear in the classroom than outdoors and due to precedence effect, all the sound appear to come from the musician
In music played outside, along side the direct sound from the musician, the indirect sound that reach the ear is echoed from maybe by only the ground while the majority of the sound from the music wanders away with the wind and in other directions as well as being absorbed such that speakers will be required to improve the sound of the music outdoors.
An atomic mass unit (symbolized AMU or amu) is defined as precisely 1/12 the mass of an atom of carbon-12. The carbon-12 (C-12) atom has six protons and six neutrons in its nucleus. In imprecise terms, one AMU is the average of the proton rest mass and the neutron rest mass.
To calculate the atomic mass of a single atom of an element, add up the mass of protons and neutrons.
Answer:
See explanation below
Explanation:
First thing to do here, is to calculate the speed of each runner. The problem states that both runners jog at a constant speed. We are given data for both runners, the starting time and the time where both of them reach the same distance.
With these data we can calculate the speed of both runners. Let's do it with runner 1:
If by t = 25 s it reach a 64 m of distance, then his speed:
V = d/t (1)
Replacing we have:
V₁ = 64 / 25 = 2.56 m/s
With this speed we can calculate the distance at t = 45 s so:
d = V * t (2)
d₁ = 2.56 * 45
<h2>
d₁ = 115.2 m</h2>
So Runner 1 will be at 115.2 from the starting point at 45 seconds.
For runner 2, he began at t = 2.5 s, but he reach the 64 m at 25 s, so his speed would be:
V₂ = 64 / (25-2.5) = 2.84 m/s
And the distance at t = 45 s
d₂ = 2.84 * 45
<h2>
d₂ = 127.8 m</h2>
Runner 2 is 127.8 m from the starting point at 45 seconds.
Hope this helps
