Question

A rock hits a window and stops in 0.15 seconds. The net force on the rock is 58N during the collision. What is the magnitude of the change in momentum of the rock?

Answer 1

Answer:

The change in momentum is  $\Delta p = 0.7 \ kg\cdot m \cdot s^{-1}$

Explanation:

From the question we are told that

    The time taken for the stone to stop is $\Delta t = 0.15 \ seconds$

    The net force on the rock is  $F = 58 \ N$

   

The impulse of the rock can be mathematically represented as

     $I = F * \Delta t$

Substituting values

     $I = 58 * 0.15$

    $I = 0.7\ kg * m * s^{-1}$

Now impulse is defined as  the rate at which momentum change

   Hence the change in momentum $\Delta p$  of the rock is equal to the impulse of the rock

 So  

       $\Delta p = I = 0.7 \ kg\cdot m \cdot s^{-1}$