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sammy [17]
3 years ago
7

A rock hits a window and stops in 0.15 seconds. The net force on the rock is 58N during the collision. What is the magnitude of

the change in momentum of the rock?
Physics
1 answer:
nlexa [21]3 years ago
7 0

Answer:

The change in momentum is  \Delta p =   0.7 \ kg\cdot m \cdot s^{-1}

Explanation:

From the question we are told that

    The time taken for the stone to stop is \Delta  t = 0.15 \ seconds

    The net force on the rock is  F =  58 \ N

   

The impulse of the rock can be mathematically represented as

     I  =  F * \Delta t

Substituting values

     I  =  58 * 0.15

    I  =  0.7\  kg * m  * s^{-1}

Now impulse is defined as  the rate at which momentum change

   Hence the change in momentum \Delta p  of the rock is equal to the impulse of the rock

 So  

       \Delta p =  I  =  0.7 \ kg\cdot m \cdot s^{-1}

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Answer:

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Explanation:

a) In this exercise we have a physical pendulum since the rod is a material object, the angular velocity is

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The rod is a homogeneous body so its center of mass is at the geometric center of the rod.

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In this exercise, the kinetic energy is requested in the lowest position, in this position the energy is maximum. For this expression to be maximum, the sine function must be equal to ±1

In the exercise it is indicated that at the lowest point the angular velocity is

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the kinetic energy is

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           K = 1/6 m L² w²

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b) for this part let's use conservation of energy

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             Em₀ = K = ½ I w²

final point. Highest point

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energy is conserved

             Em₀ = Em_f

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