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Yuliya22 [10]
3 years ago
6

When we jump on a concrete surface , the feet gets injured,why?​

Physics
2 answers:
erastovalidia [21]3 years ago
8 0

Because the gravity pulls use towards the ground and our bones can’t take the amount of weight hitting the surface

wariber [46]3 years ago
5 0

What part of your body hits the ground first?

Your legs, knees and torso can flex and accommodate some deceleration, but when you go airborne, even briefly, you accelerate downward, and that in effect increases the “weight” your body must suddenly bear in impact.

Try this at home. Get something heavy, like a box full of paperback books. Now, take go up two steps, turn around, and carefully step over the first step directly onto the ground.

Your feet really notice it don’t they. Maybe even sting a bit.

Now imagine you missed that first step accidentally, and your foot slammed down an additional 8...(more)

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A man paddles a canoe at 6 km per hour. If he paddles on a river with a current of 6 km per hour, what is the speed of the canoe
Romashka-Z-Leto [24]

Answer:

If the canoe heads upstream the speed is zero. And directly across the river is  8.48 [km/h] towards southeast

Explanation:

When the canoe moves upstream, it is moving in the opposite direction of the normal river current. Since the velocities are vector (magnitude and direction) we can sum each vector:

Vr = velocity of the river = 6[km/h}

Vc = velocity of the canoe = -6 [km/h]

We take the direction of the river as positive, therefore other velocity in the opposite direction will be negative.

Vt = Vr + Vc = 6 - 6 = 0 [km/h]

For the second question, we need to make a sketch of the canoe and we are watching this movement at a high elevation. So let's say that the canoe is located in point 0 where it is located one of the river's borders.

So we are having one movement to the right (x-direction). And the movement of the river to the south ( - y-direction).

Since the velocities are vector we can sum each vector, so using the Pythagoras theorem we have:

Vt = \sqrt{(6)^{2} +(-6)^{2} } \\Vt=8.48[km/h]

5 0
3 years ago
1. What are the units of area under the line/curve?<br> 2. Does the area have any meaning?
TiliK225 [7]

The area under the velocity time graph is 125 m and the meaning of the area is displacement.

<h3>What is area under velocity - time graph?</h3>

The area under a velocity time graph represents the displacement of the object.

total area of the graph = A1 + A2

total area of the graph = ¹/₂ (base₁)(height₁) + ¹/₂ (base₂)(height₂)

total area of the graph = ¹/₂(4)(40) + ¹/₂(3)(30)

total area of the graph = 125 m

Thus, the area under the velocity time graph is 125 m and the meaning of the area is displacement.

Learn more about velocity time graph here: brainly.com/question/4710544

#SPJ1

6 0
2 years ago
If the current in this circuit is 3 A, what must be the value of R3?<br><br><br>It's 5 Ω
Svetllana [295]

Explanation :

It is given that,

In the given figure all the three resistors are in series.

Current flowing in the circuit, I=3\ A

Voltage, V=30\ V

We know that in series circuit the current flowing in all resistors is same.

Using Ohm's law, we get:

V=IR

30\ V=3\ A(2\ \Omega+3\ \Omega+R_3)

R_3=5\ \Omega

Hence, this is the required solution.    

5 0
3 years ago
Read 2 more answers
Greg is giving a slide show presentation to a large audience. How might a laser best help him with the presentation?
gizmo_the_mogwai [7]

Explanation :

The full form of laser is Light Amplification by Stimulated Emission of Radiation. It has particles of very high energy. It points in one direction.

Greg is giving a slide show presentation to a large audience. It is very important to make the presentation informative. By using a laser, we can focus on the important part of the presentation. So that we can highlight the important points.

3 0
3 years ago
Read 2 more answers
A certain lightbulb has a tungsten filament with a resistance of 26 Ω when cold and 170 Ω when hot. If the equation R = R0 [1 +
iris [78.8K]

Answer:

Explanation: The equation that relates resistance of tungsten at different temperatures is as follows

R = R₀ [1 + α ∆T]  , R₀ is resistance at lower temperature , R is resistance at higher temperature . α is temperature coefficient of resistivity and ∆T is rise in temperature .

Putting the values

170 = 26 [1 + .0045 ∆T]

∆T = 1230.75

lower temperature = 40◦C

higher temperature = 1230 + 40

= 1270◦C

5 0
3 years ago
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