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Gnesinka [82]
3 years ago
5

Which letter (A, B, or C) shows where you should apply the most effort to lift the stone?

Physics
1 answer:
sergij07 [2.7K]3 years ago
8 0
A becuz its at da it dont got no wa
You might be interested in
I need help please and thanks
asambeis [7]

Answer:

c

Explanation:

6 0
2 years ago
What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of – 30.0 nC?
Nastasia [14]

Answer:

F=1.26*10^{-3}N

Explanation:

Assuming the pith balls as point charges, we can calculate the repulsive force between them, using Coulomb's law:

F=\frac{kq_1q_2}{d^2}

We observe that the magnitude of the electric force is directly proportional to the product of the magnitude of both signed charges(q_1,q_2) and inversely proportional to the square of the distance(d) that separates them.

Replacing the given values, where k is the Coulomb constant:

F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-30*10^{-9}C)(-30*10^{-9}C)}{(8*10^{-2}m)^2}\\F=1.26*10^{-3}N

8 0
3 years ago
Why mirrors show texts in reverse order?
bogdanovich [222]
Mirrors reflect meaning shows what would be seen if everything was turned around, therefore, it shows text backwards because if it is turned around, it is in reverse order.
7 0
3 years ago
Read 2 more answers
Read each scenario and then answer the question scenario a 120 J of work is done in 6 seconds Scenario b 160 J of work is done i
Zielflug [23.3K]

Answer:

all scenarios are using the same power

Explanation:

we know that power is defined as P(Watts)=W(Joules)/t(seconds).

When applying this formula to each of the scenarios we find:

\frac{120J}{6s}=\frac{160J}{8s}=\frac{200J}{10s}= 20W

Done

7 0
3 years ago
A capacitor consists of two closely spaced metal conductors of large area, separated by a thin insulating foil. It has an electr
Oksi-84 [34.3K]

Answer:

1 = 5.4 J

2 = 0.1979 C

3 = 5

Explanation:

Energy in a capacitor, E is

E = 1/2 * C * V²

E = 1/2 * 3000*10^-6 * 60²

E = 1/2 * 3000*10^-6 * 3600

E = 1/2 * 10.8

E = 5.4 J

E = Q²/2C = 6.53 J

E * 2C = Q²

Q² = 6.53 * 2 * 3000*10^-6

Q² = 13.06 * 3000*10^-6

Q² = 0.03918

Q = √0.03918

Q = 0.1979 C

The Capacitor, C is inversely proportional to the distance of separation, D. Thus, if D is increased by 5 to be 5D, then C would be C/5. And therefore, our energy stored in the capacitor is increased by a factor of 5.

4 0
4 years ago
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