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3 years ago

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The length of a rectangular vegetable bed is 3 feet more than twice the width. The length of the fence around the bed is 36 feet

. Find the length and with.
a) If the width of the rectangle is x, the equation is_.

b) The width of the vegetable bed is __, the length is __

1 answer:

Svetllana [295]3 years ago

8 0

B: The width of the vegetable bed is 5 feet. The length is 13 feet.

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Create an equation modeling the scenario. Use the equation to solve for the missing number. In your final answer, include the eq

Svetradugi [14.3K]

I think it’s 2(x+7)=3x

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3 years ago

Read 2 more answers

What two rational expressions sum to 2x+3/x^2-5x+4

Anni [7]

Answer:

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

Step-by-step explanation:

Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

$x^2 - 5x + 4$

$x^2 - 4x - x + 4$

$(x^2 - 4x) - (x + 4)$

$x(x - 4) - 1(x - 4)$

$(x- 1)(x - 4)$

Thus, we now have: $\frac{2x + 3}{(x- 1)(x - 4)}$

Step 2: Apply the concept of Partial Fraction

Let,

$\frac{2x + 3}{(x- 1)(x - 4)}$ = $\frac{A}{x- 1} + \frac{B}{x - 4}$

Multiply both sides by (x - 1)(x - 4)

$\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4)$ = $(\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)$

$2x + 3 = A(x - 4) + B(x - 1)$

Step 3:

Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(4) + 3 = A(4 - 4) + B(4 - 1)$

$8 + 3 = A(0) + B(3)$

$11 = 3B$

$\frac{11}{3} = B$

$B = \frac{11}{3}$

Substituting x = 1 in $2x + 3 = A(x - 4) + B(x - 1)$

$2(1) + 3 = A(1 - 4) + B(1 - 1)$

$2 + 3 = A(-3) + B(0)$

$5 = -3A$

$\frac{5}{-3} = \frac{-3A}{-3}$

$A = -\frac{5}{3}$

Step 4: Plug in the values of A and B into the original equation in step 2

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}$

$\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}$

7 0

3 years ago

What is the value of the larger zero of the function:<br><br> f(x) = 3x^2– 14x + 15?

AVprozaik [17]

Answer:

^

Step-by-step explanation:

can you plz tell me what this is is it a multiplt??

4 0

3 years ago

Write L if it is likely to happen and U if unlikely to happen.

maria [59]

Answer:

Probabilities

Likely to happen (L) Unlikely to happen (U)

a. 4/5 5/8

b. 3/5 3/8

c. 4/5 4/7

d. 0.3 0.09

e. 5/6 and 4/5 2/3

Step-by-step explanation:

Probabilities in Percentages:

a. The probability of 4/5 = 80% and 5/8 = 62.5%

b. The probability of 3/8 = 37.5% and 3/5 = 60%

c. The probability of 4/5 = 80% and 4/7 = 57%

d. The probability of 0.3 = 30% and 0.09 = 9%

e. The probability of 2/3 = 67% and 4/5 = 80% and 5/6 = 83%

b) To determine the relative values of the fractional probabilities, it is best to reduce them to their fractional or percentage terms. When this is done, the relative sizes become obvious, and then, comparisons can be made.

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3 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

6 0

3 years ago