URGENT: Find two functions f(x) and g(x) such that f[g(x)] =x but g[f(x)] does not equal x.

John invested his inheritance of $12,000 in three different funds: part in a money-market fund paying 3% interest annually; part in municipal bonds paying 4% annually; and the rest in mutual funds paying 7% annually. John invested $4,000 more in mutual funds than he invested in municipal bonds. The total interest earned in one year was $670. How much did he invest in each type of fund?

The explanation of the answer is now given as follows:

Let a, b and c represent the amount invested in money-market fund, municipal bonds and mutual funds respectively. Therefore, the sum of the three principal amounts can be represented as follows:

a + b + c = 12,000 ……………………….. (1)

Since John invested $4,000 more in mutual funds than he invested in municipal bonds, we have:

c = b + 4,000 ……………………………. (2)

The total amount of interest earned from each fund can be represented as follows:

0.03a + 0.04b + 0.07c = 670 ………………. (3)

Substituting equation (2) into equation (1), we have:

a + b + b + 4,000 = 12,000

a + 2b = 12,000 – 4,000

a + 2b = 8,000

a = 8,000 – 2b ……………………….. (4)

Also, substituting equation (2) into equation (3), we have:

0.03a + 0.04b + 0.07(b + 4,000) = 670

0.03a + 0.04b + 0.07b + 280 = 670

0.03a + 0.04b + 0.07b 0 = 670 – 280

0.03a + 0.11b = 390 ,,,,,,,,,,,,,,,,,,,,,, (5)

Substituting equation (4) into equation (5) and solve for b, we have:

0.03(8,000 – 2b) + 0.11b = 390

240 – 0.06b + 0.11b = 390

240 + 0.05b = 390

0.05b = 390 – 240

0.05b = 150

b = 150 / 0.05

b = 3,000

Substituting b = 3,000 into equation (2), we have:

c = 3,000 + 4,000

c = 7,000

Also, substituting b = 3,000 into equation (4), we have:

a = 8,000 – (2 * 3,000)

a = 8,000 – 6,000

a = 2,000

Therefore, John invested $2,000 in money-market fund, $3,000 in municipal bonds, and $7,000 in mutual funds.

8 0

3 years ago

*Asymptotes* g(x) =2x+1/x-3 Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .