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Brums [2.3K]
3 years ago
14

Compare the kinetic and potential energies of a 200 kg box being moved horizontally by a forklift at a speed of 5 m/s. The box i

s at a height of 1 m.
Physics
1 answer:
vichka [17]3 years ago
7 0
Given:

mass of the box = 200kg
velocity of the moving box = 5m/s
height of the box = 1m

Required:

The comparison of the kinetic energy and potential energy

Solution:

Kinetic energy can be calculated using the formula:

KE = 0.5(mass)(velocity)²
KE = 0.5(200kg)(5m/s)²
KE = 2500 Joules

Potential energy can be calculated using the formula:

PE = (mass)(gravity)(height)
PE = (200kg)(9.8m/s²)(1m)
PE = 1960 Joules

At the given conditions, the kinetic energy is greater than the potential energy. This means that the total energy is spent to move horizontally rather than vertically.
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A horizontal spring with stiffness 0.4 N/m has a relaxed length of 11 cm (0.11 m). A mass of 21 grams (0.021 kg) is attached and
riadik2000 [5.3K]

Answer:

0.6983 m/s

Explanation:

k = spring constant of the spring = 0.4 N/m

L₀ = Initial length = 11 cm = 0.11 m

L = Final length = 27 cm = 0.27 m

x = stretch in the spring = L - L₀ = 0.27 - 0.11 = 0.16 m

m = mass of the mass attached = 0.021 kg

v = speed of the mass

Using conservation of energy

Kinetic energy of mass = Spring potential energy

(0.5) m v² = (0.5) k x²

m v² = k x²

(0.021) v² = (0.4) (0.16)²

v = 0.6983 m/s

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4 years ago
How do I do this question?
Mkey [24]

a. 27

after that all you need to do is use the work formula as you will be able to acheive results

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Which is correct? I need to know!!
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4 years ago
If 270 watts of power is used in 42 seconds, how much work was done<br>​
navik [9.2K]

Answer: W = 11340J

Explanation:

Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below.

So this is the Formula: Power = Work / Time.

<u>Step 1:</u><em><u> Find the Formula</u></em>

P = W / T

<em><u> </u></em>

<u>Step 2: </u><u><em>Make W the subject of the equation.</em></u>

W = PT

<u>Step 3:</u><u> </u><u><em>Given.</em></u>

P = 270 Watts, T = 42 seconds

<u>Step 4:</u><u><em> Substitute these values into equation 2 .</em></u>

W = 270(42)

<u>Step 5:</u><u> </u><u><em>Simplify.</em></u>

W = 11340J

The amount of work done was 11340.

~I hope I helped you! :)~

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Explanation:

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