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Brums [2.3K]
3 years ago
14

Compare the kinetic and potential energies of a 200 kg box being moved horizontally by a forklift at a speed of 5 m/s. The box i

s at a height of 1 m.
Physics
1 answer:
vichka [17]3 years ago
7 0
Given:

mass of the box = 200kg
velocity of the moving box = 5m/s
height of the box = 1m

Required:

The comparison of the kinetic energy and potential energy

Solution:

Kinetic energy can be calculated using the formula:

KE = 0.5(mass)(velocity)²
KE = 0.5(200kg)(5m/s)²
KE = 2500 Joules

Potential energy can be calculated using the formula:

PE = (mass)(gravity)(height)
PE = (200kg)(9.8m/s²)(1m)
PE = 1960 Joules

At the given conditions, the kinetic energy is greater than the potential energy. This means that the total energy is spent to move horizontally rather than vertically.
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) each plate of a parallel-plate air-filled capacitor has an area of 0.0020 , and the separation of the plates is an electric fi
Dvinal [7]
I attached the full question.
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6 0
3 years ago
A steel spur pinion has a module of 2 mm, 17 teeth cut on the 20° full-depth system, and a face width of 20 mm. At a speed of 16
erastovalidia [21]

Answer:

The value of bending stress on the pinion 35.38 M pa

Explanation:

Given data

m = 2 mm

Pressure angle \phi = 20°

No. of teeth T = 17

Face width (b) = 20 mm

Speed N = 1650 rpm

Power = 1200 W

Diameter of the pinion gear

D = m T

D = 2 × 17

D = 34 mm

Velocity of the pinion gear

V =\pi D( \frac{N}{60} )

V = 3.14 (0.034) \frac{(1650)}{60}

V = 2.93 \frac{m}{s}

Form factor for the pinion gear is

Y = 0.303

Now

K_{v} = \frac{6.1 +0.303}{6.1} = 1.049

Force on gear tooth

F = \frac{P}{V}

F = \frac{1200}{2.93}

F = 408.73 N

Now the bending stress is given by the formula

\sigma = \frac{K_{v} F}{m b y}

\sigma = \frac{(1.049)(408.73)}{(0.002)(0.02)(0.303)}

\sigma = 35.38 M pa

This is the value of bending stress on the pinion

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