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lara [203]
3 years ago
15

Convert 22°c to fahrenheit

Physics
2 answers:
posledela3 years ago
7 0
The answer is:
71.6 <span>°F</span>
Nuetrik [128]3 years ago
4 0
F = 1.8C + 32

F = 1.8 (22) + 32

F = 39.6 + 32

F = 71.6°
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Phosphorus-32, a radioactive isotope of phosphorus-31 (atomic number 15), undergoes a form of radioactive decay whereby a neutro
dimulka [17.4K]

Answer:

The product of the decay its Sulfur-32

Explanation:

Phosphorus-32 ( lets write it _{15}^{32}P, where the number above its the atomic mass and the number below the atomic number) decays turning a neutron into a proton and emitting radiation on the form of a electron. This is the beta minus decay, and, actually, an electronic antineutrino its also produced. We can write this decay for an X isotope with a Y isotope produced as:

_{Z}^{A}X \to _{Z+1}^{A}Y + e^- + \bar{\nu_e}

where e^- its the electron, and \bar{\nu_e} the electronic antineutrino . We can see that the atomic number increases by one (cause a proton it produced and retained into the nucleus), and the atomic mass is approximately the same (there is a small difference between the neutron and proton mass, but its very small).

So, Phosphorus-32 (atomic number 15) will turn to an element with atomic number 16, and atomic mass 32, as:

_{15}^{32}P \to _{15+1}^{32}Y + e^- + \bar{\nu_e}.

_{15}^{32}P \to _{16}^{32}Y + e^- + \bar{\nu_e}.

The Y isotope must have an atomic number of 16 and an atomic mass of 32. The element with atomic number 16 its Sulfur (S), so, our decay its

_{15}^{32}P \to _{16}^{32}S + e^- + \bar{\nu_e}.

and the product of such decay its Sulfur-32

5 0
3 years ago
According to Bohr each orbit an electron could travel in had a certain amount of ________ associated with it.
Lena [83]
The awnser to your problem would be a as in energy
6 0
3 years ago
a race car driver must average 203 km/h over the course of a time trial lasting ten laps. If the first nine laps were done at 19
sashaice [31]

Answer:

speed for last lap is 247.89 km/h

Explanation:

given data

velocity v1 = 203 km/h

velocity v2 = 199 km/h

no of lap n = 10

to find out

average speed for last lap

solution

we consider here distance d for 1 lap

so in first 9 lap time taken is

t1 = distance / velocity v2

t1 = 9d / 199    ...............1

and

for 10 lap time is

t2 = 10d / 203   .............2

so from 1 and 2 equation time for last lap

last lap time t3  = t2 - t1    

t3 = 10d / 203  -  9d / 199

t3 = 0.004034 d

so speed for last lap is

speed = distance / time

speed = d / 0.004034 d

speed = 247.89 km/h

so speed for last lap is 247.89 km/h

4 0
3 years ago
How would the model change as the atom forms bonds? The third shell would have eight electrons after the atom gains seven electr
atroni [7]

Answer:

The third shell would be empty, so the eight electrons on the second level would be the outermost after the atom lost one electron

Explanation:

When an atom is bonded with other atoms, a more stable configuration must be reached, which is why the energy of the molecule is less than the energy of the individual atoms, for this to happen in general, electrons are shared or lost and gained in each atom, depending on the electronegative of the same.

If we analyze an atom within the molecule, its last shell is full, in the case of atoms with few electrons in this shell, they are lost and in the case of many electors in this shell, it gains electrons to have eight (8) in total.

When reviewing the different answers, the correct one is:

* The third shell would be empty, so the eight electrons on the second level would be the outermost after the atom lost one electron

4 0
2 years ago
Read 2 more answers
A 20-kg block slides down a fixed rough curved track The block has a speed of 5 0 m/s after its height above a horizontal surfac
Crank

Answer:

U = 102.8 J (100 J to two significant digits)

Explanation:

potential energy converted = 20(9.8)(1.8) = 352.8 J

kinetic energy at base of track = ½(20)5.0² = 250 J

energy (work) of friction 352.8 - 250 = 102.8 J

8 0
3 years ago
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