Question

The position of a particle s given by x=3-2t+3t^2. What is its instantaneous velocity and instantaneous acceleration as t=3.

Answer 1

Explanation:

velocity = dx/dt

$\frac{dx}{dt} = 6t - 2 = 16$

acceleration =

$\frac{ {d}^{2}x }{d {t}^{2} } = 6$