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marusya05 [52]
3 years ago
14

The position of a particle s given by x=3-2t+3t^2. What is its instantaneous velocity and instantaneous acceleration as t=3.

Physics
1 answer:
Leno4ka [110]3 years ago
5 0

Explanation:

velocity = dx/dt

\frac{dx}{dt}  = 6t - 2 = 16

acceleration =

\frac{ {d}^{2}x }{d {t}^{2} }  = 6 \ \\

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7 0
3 years ago
Read 2 more answers
If a ball is thrown straight up into the air with an initial velocity of 65 ft/s, its height in feet after t seconds is given by
fgiga [73]

Answer:

a) v_{1}=\frac{(62.5-66)ft}{(2.5-2)s}=-7ft/s

v_{2}=\frac{(65.94-66)ft}{(2.1-2)s}=-0.6ft/s

v_{3}=\frac{(66.0084-66)ft}{(2.01-2)s}=0.84ft/s

v_{4}=\frac{(66.001-66)ft}{(2.001-2)s}=1ft/s

b) v=65-32(2)=1ft/s

Explanation:

From the exercise we got the ball's equation of position:

y=65t-16t^{2}

a) To find the average velocity at the given time we need to use the following formula:

v=\frac{y_{2}-y_{1}  }{t_{2}-t_{1}  }

Being said that, we need to find the ball's position at t=2, t=2.5, t=2.1, t=2.01, t=2.001

y_{t=2}=65(2)-16(2)^{2} =66ft

y_{t=2.5}=65(2.5)-16(2.5)^{2} =62.5ft

v_{1}=\frac{(62.5-66)ft}{(2.5-2)s}=-7ft/s

--

y_{t=2.1}=65(2.1)-16(2.1)^{2} =65.94ft

v_{2}=\frac{(65.94-66)ft}{(2.1-2)s}=-0.6ft/s

--

y_{t=2.01}=65(2.01)-16(2.01)^{2} =66.0084ft

v_{3}=\frac{(66.0084-66)ft}{(2.01-2)s}=0.84ft/s

--

y_{t=2.001}=65(2.001)-16(2.001)^{2} =66.001ft

v_{4}=\frac{(66.001-66)ft}{(2.001-2)s}=1ft/s

b) To find the instantaneous velocity we need to derivate the equation

v=\frac{df}{dt}=65-32t

v=65-32(2)=1ft/s

7 0
3 years ago
How are the components of a heterogeneous mixture distributed?
Lena [83]

Answer:

heterogeneous mixture has components that are not evenly distributed. This means that you can easily distinguish between the different components.

3 0
3 years ago
The top of the pool table is 0.810 m from the floor. the placement of the tape is such that 0 m is aligned with the edge of the
8090 [49]
Compute first for the vertical motion, the formula is:

y = gt²/2 

0.810 m = (9.81 m/s²)(t)²/2 

t = 0.4064 s 


whereas the horizontal motion is computed by: 

x = (vx)t 

4.65 m = (vx)(0.4064 s) 

4.65 m/ 0.4064s = (vx)

(vx) = 11.44 m / s
So look for the final vertical speed. 

(vy) = gt 

(vy) = (9.81 m/s²)(0.4064 s) 

(vy) = 3.99 m/s 


speed with which it hit the ground: 

v = sqrt[(vx)² + (vy)²] 

v = sqrt[(11.44 m/s)² + (3.99 m/s)²] 

v = 12.12 m / s
6 0
3 years ago
He vector parts that add up to the resultant are called ____.
cupoosta [38]

1. Answer: components

A two dimensional vector can be divided into two parts called horizontal component and vertical component.

A three dimensional vector can be divided into three components: one along x-axis, one along y-axis and one along z-axis.

Hence, the vector parts that add up to the resultant are called components.

2. Answer: 5 miles.

The resultant distance along the straight line from the starting point to the end point would be the displacement.

The displacement would be equal to the magnitude of the hypotenuse formed in the right triangle.

Displacement, d=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5 miles

3. Answer: Scalar

A scalar quantity has only magnitude. For example, speed and distance are scalar quantities and can be normally added to find the total.

A vector quantity has both magnitude as well as direction. The components are summed according to vector addition rules. For example, velocity, acceleration, force etc.

5 0
3 years ago
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