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ki77a [65]
3 years ago
8

What's 5x2 get it right and i will give you the cool crown :3

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
7 0
It’s 10.
It’s the same thing as 5+5
MariettaO [177]3 years ago
4 0
The answer to this very difficult question is 10 :)
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Tape diagram to subtract 33-19
Tpy6a [65]
Well 33 - 19 = 14 and what do u mean tape diagram?
3 0
3 years ago
What is the answer to-<br> solve x^2+5x+6=0
Alika [10]
<span>x^2+5x+6=0
(x+3)(x+2) = 0

x+3 = 0
x = -3

</span>x+2 = 0
x = -2
<span>
Solutions: x = -3 and x = -2

</span>
8 0
3 years ago
Can somebody help me with my math??? <br> Answer ASAP
Basile [38]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Find the prime factorization of each number (please)<br><br>891<br>23<br>504<br>230
patriot [66]

Answer:

  • 891 = 3^4 · 11
  • 23 = 23
  • 504 = 2^3 · 3^2 · 7
  • 230 = 2 · 5 · 23

Step-by-step explanation:

23 is a prime number. That fact informs the factorization of 23 and 230.

The sums of digits of the other two numbers are multiples of 9, so each is divisible by 9 = 3^2. Dividing 9 from each number puts the result in the range where your familiarity with multiplication tables comes into play.

  891 = 9 · 99 = 9 · 9 · 11 = 3^4 · 11

___

  504 = 9 · 56 = 9 · 8 · 7 = 2^3 · 3^2 · 7

___

  230 = 10 · 23 = 2 · 5 · 23

_____

<em>Comment on divisibility rules</em>

Perhaps the easiest divisibility rule to remember is that a number is divisible by 9 if the sum of its digits is divisible by 9. That is also true for 3: if the sum of digits is divisible by 3, the number is divisible by 3. Another divisibility rule fall out from these: if an even number is divisible by 3, it is also divisible by 6. Of course any number ending in 0 or 5 is divisible by 5, and any number ending in 0 is divisible by 10.

Since 2, 3, and 5 are the first three primes, these rules can go a ways toward prime factorization if any of these primes are factors. That is, it can be helpful to remember these divisibility rules.

6 0
3 years ago
You invested money in a fund and each month you receive a payment for your investment. Over the first four months, you received
Alexus [3.1K]

Money received in tenth month: $104

Difference between explicit formula and a recursive formula is: the use of (n-1)th term, nth term and the common difference (d) brings a great difference between the two formulae of an arithmetic progression.

<h3>What is arithmetic progression?</h3>

A series of numbers called an arithmetic progression or arithmetic sequence (AP) has a constant difference between the terms.

Given:

  • Money received in first four months: $50, $52, $55, %59.

To find: Money received in tenth month.

Finding:

As we can see, the pattern followed here is: increment in each amount received each month by $1. Thus it is an arithmetic progression.

That is: 50, 52 (0+2), 55 (2+3), 59 (2 + 3 + 4) and so on.

Thus, for the tenth month, we can use the formula of recursion, given by: a_n=a_{n-1}+n, n ≥ 1.

For a₁ = 50, a₂ = a₁ + 2

=> a₂ = 50 + 2

This way, a₅ = a₄ + 5

=> a₅ = 59 + 5 = 64

a₆ = a₅ + 6

=> a₆ = 64 + 6 = 70

a₇ = a₆ + 7

=> a₇ = 70 + 7 = 77

a₈ = a₇ + 8

=> a₈ = 77 + 8 = 85

a₉ = a₈ + 9

=> a₉ = 85 + 9 = 94

a₁₀ = a₉ + 10

=> a₁₀ = 94 + 10 = 104

Thus, the payment received in tenth month will be $104.

(b) Difference between explicit formula and recursive formula of an arithmetic progression:

  • The first term of a recursive formula is a₁ and the formula for the nth term uses the first term and the common difference, d. One example of a recursive formula is a_n=a_{n-1}+d.
  • A formula for the nth term in an explicit formula would include the initial term a₁, the common difference d, and the term number, n. The equation a_n = a_1 + (n-1)d.

To learn more about arithmetic Progressions, refer to the link: brainly.com/question/6561461

#SPJ4

6 0
1 year ago
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